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Lapatulllka [165]
3 years ago
6

What does 15cubed look like in exspanded form

Mathematics
1 answer:
Mashutka [201]3 years ago
6 0
15^3 = 15\times 15\times 15=3,375\\\\\sf in~expanded~form:\\\boxed{3,000 + 300 + 70+5}
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State of the given functions are inverses. Part 3. NO LINKS!!!!​
Effectus [21]

Answer:

9.

h(x)=-x-1

let y =-x-1

interchanging role of x & y

x=-y-1

y=-x-1

h-¹(x)=-x-1

again

f(x)=(2-3x)/2

let

y=(2-3x)/2

interchanging role of x & y

x=(2-3y)/2

2x-2=-3y

y=(2-2x)/3

f-¹(x)=(2-2x)/3

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10.

f(x)=-x+3

let y=-x+3

interchanging role of x & y

x=-y+3

y=3-x

f-¹(x)=-x+3

equal to g(x)=-x+3

<u>Given function are</u><u> inverse of each other.</u>

8 0
3 years ago
Read 2 more answers
What number is 10 times bigger than 30​
svlad2 [7]

Answer:

300

Step-by-step explanation:

10 x 30= 300

3 0
3 years ago
Please help!!! thank you :)))
Lunna [17]

Answer:

i dont know this one

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What are the vertices of triangle A'B'C' produced by (x, y) -&gt; (x+5, y-2)?
lara [203]

Answer:

The vertices of triangle A'B'C' produced by (x, y)  →  (x+5, y-2)  will be:

  • A'(8, -2)
  • B'(8, 0)
  • C'(5, -5)

Step-by-step explanation:

Given the vertices of an original triangle ΔABC such that

  • A = (3, 0)
  • B = (3, 2)
  • C = (0, -3)

As the rule of translation is given by

Translation: (x, y)  →  (x+5, y-2)

So, after the translation the vertices of the original triangle ΔABC will be translated as:

A = (3, 0)  → (x+5, y-2)  ⇒ (3+5, 0-2) = A'(8, -2)

B = (3, 2)  →  (x+5, y-2)  ⇒ (3+5, 2-2) = B'(8, 0)

C = (0, -3) → (x+5, y-2)  ⇒ (0+5, -3-2) = C'(5, -5)

Therefore, the vertices of triangle A'B'C' produced by (x, y)  →  (x+5, y-2)  will be:

  • A'(8, -2)
  • B'(8, 0)
  • C'(5, -5)
7 0
3 years ago
The triangle shown on the graph above is rotated 90 degrees clockwise about the original to form triangle P’Q’R which of the fol
azamat

Hey there! I'm happy to help!

When rotating a point 90 degrees clockwise about the origin, our original point (x,y) becomes (-y,x), because it is now at a negative y-value.

We see that our point P is at (1,2). We can use this rotation formula to find the coordinates of P' (the new spot where P is)/

(x,y)⇒(-y,x)

(1,2)⇒(-2,1)

Therefore, the coordinates of the point P' are (-2,1).

Have a wonderful day! :D

4 0
3 years ago
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