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Mamont248 [21]
3 years ago
5

NEED HELP ASAP Does this Intro simulation support the law of conservation of energy? Use evidence to explain why or why not.

Physics
1 answer:
TiliK225 [7]3 years ago
6 0

is this the skater one? If so, it does support the law of conservation of energy because at the top of the ramp the skater has the same amount of potential energy their total energy and as the skater goes down the ramp their potential energy lowers as their kinetic energy rises.

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Which of the following temparature is approximately equal to room temperature
Artist 52 [7]

Hello there! :)

\huge\boxed{\text{C. 293K}}

Room temperature is approximately 20°C.

We can automatically eliminate choices B and D since they are not equal to 20°C.

Since some choices use the Kelvin scale, we can convert from Celsius to Kelvin using a simple formula:

K = C° + 273

Find room temperature in degrees <u>Kelvin</u>:

K = 20° + 273

K = 293°

Thus, the correct choice would be <u>C. 293K.</u>

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3 years ago
What is refraction of light?
prohojiy [21]

Answer:

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Explanation:

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What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??
Fittoniya [83]

Answer:

F = 37.5 N

Explanation:

It is given that,

Mass of the object is 5 kg

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We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,

F = m

F=5\times 7.5\\\\F=37.5\ N

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4 0
4 years ago
Two skaters collide and grab on to each other on frictionless ice. One of them, of mass 66.0 kg , is moving to the right at 2.00
ivann1987 [24]

Answer:

The velocity of skaters after collision is 0.55 m/s and they are moving to the left

Explanation:

Consider m₁ and m₂ are the masses of two skaters and their initial velocity be v₁ and v₂ respectively.

Consider the velocity along right direction as positive while negative for left direction.

According to the problem,

Mass of first skater, m₁ = 66.0 kg

Mass of second skater, m₂ = 75.0 kg

Velocity of first skater, v₁ = + 2.00 m/s

Velocity of second skater, v₂ = -2.80 m/s

Since, the two skaters grab each other after collision. Hence, they are moving with same final velocity v.

Applying conservation of linear momentum,

Momentum before collision = Momentum after collision

m₁v₁ + m₂v₂ = (m₁+m₂)v

Substitute the suitable values in the above equation.

66 x 2 - 75 x 2.8 = (66 + 75 )v

v= \frac{-78}{141}

v = -0.55 m/s

The negative sign denotes that both the skaters are moving in the left direction.

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4 years ago
What is the charge of the negative sphere
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Answer:

electrons

Explanation:

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