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vesna_86 [32]
3 years ago
8

One hazard of space travel is debris left by previous missions. there are several thousand objects orbiting earth that are large

enough to be detected by radar, but there are far greater numbers of very small objects, such as flakes of paint. calculate the force exerted in newtons by a 0.160 mg chip of paint that strikes a spacecraft window at a relative speed of 3.00 ✕ 103 m/s and sticks, given the collision lasts 6.00 ✕ 10−8 s. (enter the magnitude.)
Physics
1 answer:
iren2701 [21]3 years ago
4 0
The chip, during the collision, has a change in momentum:
Δp = m · (v₂ - v₁)

The final speed is equal to zero, since it sticks to the spacecraft, therefore:
Δp = m · v
      = 1.6×10⁻⁷ · 3×10³
      = 4.8×10⁻⁴ kg·m/s
where we transformed the mass into the proper units of measurement (kg).

This change in momentum is equal to the impulse J:
Δp = J = F · t

We can solve for F
F = J / t = <span>Δp / t
   = </span>4.8×10⁻⁴ / 6×10⁻⁸
   = 8.0×10³ N

Hence, <span>the force exerted by the chip on the spacecraft is F = 8000N.</span>
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The solution of Sulfuric Acid (H2SO4) has the following mole fractions:

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To solve this problem the formula and the procedure that we have to use is:

  • n = m / MW
  • = ∑ AWT
  • mole fraction = moles of A component / total moles of solution
  • ρ = m /v

Where:

  • m = mass
  • n = moles
  • MW = molecular weight
  • AWT = atomic weight
  • ρ = density
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Information about the problem:

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  • v(solution) = 100 ml
  • ρ (solution)= 1.094 g/ml
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  • mole fraction(H2SO4) = ?
  • mole fraction(H2O) = ?

We calculate the moles of the H2SO4 and of the H2O from the Pm:

MW = ∑ AWT

MW (H2SO4)= AWT (H) * 2 + AWT (S) + AWT (O) * 4

MW (H2SO4)= (1 g/mol * 2) + (32,064 g/mol) + (16 g/mol * 4)

MW (H2SO4)= 2 g/mol + 32 g/mol + 64 g/mol

MW (H2SO4)=  98 g/mol

MW (H2O)= AWT (H) * 2 + AWT (O)

MW (H2O)= (1 g/mol * 2) + (16 g/mol)

MW (H2O)= 2 g/mol + 16 g/mol

MW (H2O)=  18 g/mol

Having the Pm we calculate the moles of H2SO4:

n = m / MW

n(H2SO4) = m(H2SO4) / MW (H2SO4)

n(H2SO4) = 17.75 g / 98 g/mol

n(H2SO4) = 0.1811 mol

With the density and the volume of the solution we get the mass:

ρ(solution)= m(solution) /v(solution)

m(solution) = v(solution) * ρ(solution)

m(solution) = 100 ml * 1.094 g/ml

m(solution) = 109.4 g

Having the mass of the solution we calculate the mass of the water in the solution:

m(H2O) = m(solution) - m solute (H2SO4)

m(H2O) = 109.4 g - 17.75 g

m(H2O) = 91.65 g

We calculate the moles of H2O:

n = m / MW

n(H2O) = m(H2O) / MW (H2O)

n(H2O) = 91.65 g / 18 g/mol

n(H2O) = 5.092  mol

We calculate the total moles of solution:

total moles of solution = n(H2SO4) + n(H2O)

total moles of solution = 0.1811 mol + 5.092  mol

total moles of solution = 5.2731 mol

With the moles of solution we can calculate the mole fraction of each component:

mole fraction (H2SO4)= moles of (H2SO4) / total moles of solution

mole fraction (H2SO4)= 0.1811 mol / 5.2731 mol

mole fraction (H2SO4)= 0.034

mole fraction (H2O)= moles of (H2O) / total moles of solution

mole fraction (H2O)= 5.092  mol / 5.2731 mol

mole fraction (H2O)= 0.966

<h3>What is a solution?</h3>

In chemistry a solution is known as a homogeneous mixture of two or more components called:

  • Solvent
  • Solute

Learn more about chemical solution at: brainly.com/question/13182946 and brainly.com/question/25326161

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Explanation:

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