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4 years ago

What happens to an object as it absorbs radiant energy?

2 answers:

8 0

What absorbs radiant energy?<span>Radiant energy is used for radiant heating. It can be generated electrically by infrared lamps, or can be absorbed from sunlight and used to heat water. The heat energy is emitted from a warm element (floor, wall, overhead panel) and warms people and other objects in rooms rather than directly heating the air.</span>

Delvig [45]4 years ago

5 0

It's temperature increases.

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qual charges, one at rest, the other having a velocity of 104 m/s, are released in a uniform magnetic field. Which charge has th

Yakvenalex [24]

Answer:

The correct option is D

Explanation:

From the question we are told that

The speed of the first charge is $v = 0 \ m/s$

This is because it is at rest

The speed of the second charge is $v = 10^{4} \ m/s$

Generally the force exerted by a magnetic field on a charge is mathematically represented as

$F_q = q * v * B sin \theta$

Now looking at this above equation we can see that $F_q$ can only be maximum at $\theta = 90 ^o$ and this only obtained when the direction of the charge (i.e its velocity ) is perpendicular to the direction of the magnetic field

so the correct option for this question is D

4 0

3 years ago

Rank the six combinations of electric charges on the basis of the electric force acting on q1.

loris [4]

Answer:

Largest; options A & B

2nd largest; Option F

3rd Largest; Option D

Smallest; Options E & C

Explanation:

Looking at the charges, basically, the net force of the charge q1 is the sum of charges q2 and q3.

When 2 charges are opposite, the force will be attractive but if they are same, then the force will be repulsive.

Thus, the order of the forces is;

I) Largest: q1= +1nC, q2= -1nc, q3= -1nc and (q1= -1nC, q2= +1nc, q3= +1nc)

II) Second largest is: q1= +1nC, q2= -1nc, q3= +1nc

III) Third largest: q1= +1nC, q2= +1nc, q3= -1nc

IV) Smallest: (q1= -1nC, q2= -1nc, q3= -1nc) and (q1= +1nC, q2= +1nc, q3= +1nc)

6 0

3 years ago

Do you support trucks are identical each box loaded on the truck has the same mask choose the truck that has the greatest force

Anestetic [448]

gravitational force of earth is given by

$F = mg$

so here the force will depend on the product of mass and gravity

so here force will be more if we took the condition of more masses

so here in 3rd figure

there will be maximum force of gravity on it

because it will have 6 boxes so there will be maximum mass

So figure of truck with 6 boxes on it is correct answer

7 0

4 years ago

When switched on, the grinding machine accelerates from rest to its operating speed of 3550 rev/min in 10 seconds. When switched

Paraphin [41]

Answer:

During start total turns

$N_1 = 296 turn$

After half of the time total turns

$N_3 = \frac{29.6 + 0}{2}(5) = 74 turns$

Total number of turns during it stop

$N_2 = \frac{59.17 + 0}{2}(31) = 917 turn$

After half of the time total turns

$N_4 = 688 turns$

Explanation:

Initially the machine is at rest and then starts rotating with speed 3550 rev/min

now we will have

$f = \frac{3550}{60} = 59.17 rev/s$

now we know that it took 10 s to reach the speed

so angular acceleration is given as

$\alpha = \frac{\omega_f - \omega_i}{t}$

$\alpha = \frac{59.17- 0}{10} = 5.917 rev/s^2$

now it stops in 31 s so the angular deceleration is given as

$\alpha_2 = -\frac{59.17}{31} = -1.91 rev/s^2$

now initially number of turn to reach the given speed

$N_1 = \frac{59.17 + 0}{2}(10) = 296 turn$

number of turns during it stop

$N_2 = \frac{59.17 + 0}{2}(31) = 917 turn$

Now during startup speed after t = 5 s is given as

$\omega_1 = (5.917)(5) = 29.6 rev/s$

$N_3 = \frac{29.6 + 0}{2}(5) = 74 turns$

now during it stop the speed after half the time is given as

$\omega_2 = 59.17 - (1.91)(15.5) = 29.56 rev/s$

now the number of turns is given as

$N_4 = \frac{59.17 + 29.56}{2}(15.5)$

$N_4 = 688 turns$

5 0

3 years ago

A street light is at the top of a 19 foot tall pole. A woman 5.25 feet tall walks towards the pole with a speed of 7ft/sec along

bezimeni [28]

Answer:

The tip of her shadow is moving at the speed of 9.66 ft/sec

Explanation:

The height of the street light = 19 feet

The height of the woman = 5.25 feet

Distance between the woman and the base of the pole, x = 35 ft

The speed of the woman towards the pole, dx/dt = 7ft/sec

The distance from the base of the streetlight to the tip of the woman's shadow = y

The distance from the woman to the tip of her shadow = y - x

The diagram illustrating this description is shown below

Using similar triangle:

$\begin{gathered} \frac{19}{5.25}=\text{ }\frac{y}{y-x} \\ 19(y-x)\text{ = 5.25y} \\ 19y-19x\text{ = 5.25y} \\ 19y-5.25y\text{ = 19x} \\ 13.75y\text{ = 19x} \\ y\text{ = }\frac{19}{13.75}x \\ y\text{ = }1.38x \end{gathered}$

Find the derivative of both sides with respect to time, t

$\begin{gathered} \frac{dy}{dt}=\text{ 1.38}\frac{dx}{dt} \\ \frac{dy}{dt}=\text{ 1.38(7)} \\ \frac{dy}{dt}\text{ = }9.66\text{ ft/sec} \end{gathered}$

The tip of her shadow is moving at the speed of 9.66 ft/sec

7 0

1 year ago