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Tomtit [17]
3 years ago
6

How was bohr atomic model similar to Rutherford's model​

Physics
2 answers:
saul85 [17]3 years ago
7 0

Answer:

it described a nucleus surrounded by a large volume of space

Explanation:

How was Bohr's atomic model similar to Rutherford's model? it described a nucleus surrounded by a large volume of space. ... Electrons travel around the nucleus in fixed energy levels with energies that vary from level to level. C) Electrons travel around the nucleus in fixed energy levels with equal amounts of energy.

Chapter 4 Review (Advanced) Flashcards | Quizlet

https://quizlet.com/16490497/chapter-4-review-advanced-flash-cards/

Juliette [100K]3 years ago
6 0
Both believe that an atom contains negative charges and positive charges.
But both were different in the placement of charges
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When magnesium fluoride reacts with iodine, the products are fluorine and magnesium iodide. What would the equation be?
likoan [24]

Answer:

Explanation:

Every chemical reaction can be represented by simple chemical equations that shows how compounds are combining to give some products.

Such reactions are usually made up of:

     Reactants on the left hand side

     Products on the right hand side

            Reactants  →  Products

In this given problem;

            Reactants are :   Magnesium fluoride  = MgF₂

                                             Iodine in form of Iodide   = I₂

           Product : Magnesium iodide  = MgI₂

             

               MgF₂   +     I₂    →       MgI₂   +   F₂

   

                             

   

7 0
3 years ago
In science though,what is it mainly used for????
erik [133]
It is mainly used to give facts about living organisms

6 0
3 years ago
Read 2 more answers
Drag the titles to the correct boxes to complete the pairs.
PilotLPTM [1.2K]
Can you input a picture??
5 0
3 years ago
A 40 cm wire with a radius of 3 cm is oriented along the y axis and carries a current of 2 A. What is the magnitude of the magne
ZanzabumX [31]

Answer:

a) B = 1.99 x 10⁻⁴ Tesla

b) B = 0.88 x 10⁻⁴ Tesla

Explanation:

According to Biot - Savart Law, the magnetic field due to a currnt carrying straight wire is given as:

B = μ₀ I L/4πr²

where,

μ₀ = permebility of free space = 1.25 x 10⁻⁶ H m⁻¹

I = current = 2 A

L = Length of wire = 40 cm = 0.4 m

a)

r = radius of magnetic field = 2 cm = 0.02 m

Therefore,

B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.02 m)²

<u>B = 1.99 x 10⁻⁴ Tesla</u>

<u></u>

b)

r = radius of magnetic field = 3 cm = 0.03 m

Therefore,

B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.03 m)²

<u>B = 0.88 x 10⁻⁴ Tesla</u>

7 0
3 years ago
Is a force necessary to keep an object in motion?
weqwewe [10]
Well according to Newton’s first law of motion, a body will remain in the state of rest or linear motion provided that an *external force* has been applied. So no, a force doesn’t need to keep a body to remain in linear motion, because F=ma, during uniform linear motion velocity is constant, hence acceleration is zero, so F=0
5 0
2 years ago
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