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Tomtit [17]
3 years ago
6

How was bohr atomic model similar to Rutherford's model​

Physics
2 answers:
saul85 [17]3 years ago
7 0

Answer:

it described a nucleus surrounded by a large volume of space

Explanation:

How was Bohr's atomic model similar to Rutherford's model? it described a nucleus surrounded by a large volume of space. ... Electrons travel around the nucleus in fixed energy levels with energies that vary from level to level. C) Electrons travel around the nucleus in fixed energy levels with equal amounts of energy.

Chapter 4 Review (Advanced) Flashcards | Quizlet

https://quizlet.com/16490497/chapter-4-review-advanced-flash-cards/

Juliette [100K]3 years ago
6 0
Both believe that an atom contains negative charges and positive charges.
But both were different in the placement of charges
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A car with a mass of 1100kg is moving in a circular curve at a uniform velocity of 15m/s
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Centripetal force = (mv^2)/r
so r = (mv^2)/ force = 246500 / 1100 = 224 m
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3 years ago
X-Rays at different wavelengths provide scientists studying objects in space with information about which of the following?
olganol [36]

Answer:

object composition

Explanation:

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Calculating Orbital Period The Hubble Space Telescope (HST) orbits 569 km above Earth’s surface. If HST has a tangential speed o
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Consider the following distribution of objects: a 2.00-kg object with its center of gravity at (0, 0) m, a 2.20-kg object at (0,
adelina 88 [10]

Answer:

body position 4 is (-1,133, -1.83)

Explanation:

The concept of center of gravity is of great importance since in this all external forces are considered applied, it is defined by

               x_cm = 1 /M   ∑ x_{i} m_{i}

               y_cm = 1 /M   ∑ y_{i} mi

Where M is the total mass of the body, mi is the mass of each element

give us the mass and position of this masses

body 1

m1 = 2.00 ka

x1 = 0 me

y1 = 0 me

body 2

m2 = 2.20 kg

x2 = 0m

y2 = 5 m

body 3

m3 = 3.4 kg

x3 = 2.00 m

y3 = 0

body 4

m4 = 6 kg

    x4=?

   y4=?

mass center position

x_cm = 0

y_cm = 0

let's apply to the equations of the initial part

X axis

    M = 2.00 + 2.20 + 3.40

    M = 7.6 kg

    0 = 1 / 7.6 (2 0 + 2.2 0 + 3.4 2 + 6 x4)

     x4 = -6.8 / 6

     x4 = -1,133 m

Axis y

    0 = 1 / 7.6 (2 0 + 2.20 5 +3.4 0 + 6 y4)

    y4 = -11/6

    y4 = -1.83 m

body position 4 is (-1,133, -1.83)

7 0
3 years ago
Which statements describe a situation with a displacement of zero? Check all that apply.traveling south for 30 miles, then turni
cluponka [151]

Answer:

• riding on a Ferris wheel whose entrance and exit are the same

• walking around the block, starting from and ending at the same house

• running exactly one lap around a racetrack

Explanation:

Displacement simply means the.change in position of an object. In a situation whereby the initial and final position are thesame, the displacement will be zero.

The statements that describe a situation with a displacement of zero include:

• riding on a Ferris wheel whose entrance and exit are the same

• walking around the block, starting from and ending at the same house

• running exactly one lap around a racetrack

5 0
3 years ago
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