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solong [7]
3 years ago
5

Which of the following could be represented using a continuous probability distribution?

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
8 0

Answer:

B. The frequency of temperatures throughout the day in Florida on April 25th.

adelina 88 [10]3 years ago
7 0

Answer:

b) The frequency of temperatures throughout the day in Florida on April 25th

Step-by-step explanation:

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Of 30 students, 1/3 play sports. Of those who play sports, 2/5 play soccer.
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Answer: 10 or 12

Step-by-step explanation:

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How do you simplify the following equation?<br><br> √64x²
mr_godi [17]
\sqrt{64 x^{2} }  
same thing as:
\sqrt{8*8*x*x}

there are two 8's and two x's in there so they can come out to give you the answer 8x
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If 9: x = x:4, then x =
IceJOKER [234]

Answer:

Step-by-step explanation:

9:x = x :4

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4 0
3 years ago
Choose the option with the proper number of sig figs
marishachu [46]
\text{ 2 }\times10^8

Explanation:\begin{gathered} \text{Given:} \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1} \end{gathered}

let's break down the expression to get the final result:

\begin{gathered} \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = }\frac{9}{4.5}\times\text{ }\frac{10^9}{10^1} \\ \frac{9}{4.5}\text{ = }\frac{9\text{ }\times\text{ 10}}{4.5\text{ }\times\text{ 10}}\text{ = }\frac{90}{45} \\ \frac{9}{4.5}\text{ = }2 \\  \\ \frac{10^9}{10^1}\colon\text{ when we divide exponents with same base, } \\ we\text{ take one of the base and combine the exponents by subtracting them:} \\ \frac{10^9}{10^1}=10^{9-1} \\ \frac{10^9}{10^1}=10^8 \end{gathered}\begin{gathered} \frac{9}{4.5}\times\text{ }\frac{10^9}{10^1}\text{ = 2 }\times10^8 \\  \\ \text{when dividing decimals, }the\text{ least number of }significant\text{ }figures\text{ in the problem}, \\ \text{ }\det ermines\text{ the significant figures in the answer} \\ 9\text{ = 1 significant, 4.5 = 2 significant} \\ \text{The least significant is 1} \\  \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = 2 }\times10^8 \end{gathered}

6 0
1 year ago
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