PLEASE PLEASEPLEASE HELP HELP HELP ME IU BEG YOU

A factory processes 1,560 ounces of olive oil per hour. The oil is packaged into 24-ounce bottles. How many bottles dose the fac

lozanna [386]

Divide the total amount of olive oil by the amount packaged into an individual bottle.

1560 / 24 = 65 bottles per hour

5 0

2 years ago

Read 2 more answers

In the U.S. More male babies are born than females. In 1998 some 2,265,031 males were born and 2,287,419 females were born. Find

suter [353]

Answer: The empirical probability that the individual being born is a male = 0.498

Step-by-step explanation:

Given the following :

Number of males born =2,265,031

Number of females born = 2,287,419

Empirical probability is given as :

P( A) =( Number of possible outcomes of event A ÷ Total number of events)

Total number of events = (number of males born + number of females born)

Total number of events = (2,265,031 + 2,287,419) = 4552450

Probability(individual being born is a boy) =

(Number of males born ÷ Total number of children born)

=2265031÷(2265031+2287419) = 0.49754110424057

Therefore, the empirical probability that the individual being born is a male = 0.498

3 0

2 years ago

Read 2 more answers

What is the approximated answer for:t{39}

WITCHER [35]

It’s 40 because it’s closer to 40 than 30

3 0

3 years ago

Read 2 more answers

In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6977subjects randomly selec

kirza4 [7]

Answer:

Given :An Internet survey was e-mailed to 6977 subjects randomly selected from an online group involved with ears. There were 1337 surveys returned.

To Find : Use a 0.01 significance level to test the claim that the return rate is less than 20%.

Solution:

n = 6977

x = 1337

We will use one sample proportion test

$\widehat{p}=\frac{x}{n}$

$\widehat{p}=\frac{1334}{6977}$

$\widehat{p}=0.1911$

We are given that the claim is the return rate is less than 20%.

$H_0:p=0.2\\H_a:p$

Formula of test statistic = $\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

= $\frac{0.1911-0.2}{\sqrt{\frac{0.2(1-0.2)}{6977}}}$

= $−1.858$

Refer the z table

P(z<-1.85)=0.0332

Significance level = 0.01=α

Since p value > α

So, we accept the null hypothesis .

So,the claim that the return rate is less than 20% is false.

7 0

2 years ago

there are 75 students in school band 45 students play woodwind instruments what percent of students play woodwinds

Ratling [72]

45/75 play woodwind
that simplified is 3/5

8 0

3 years ago

Read 2 more answers