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nasty-shy [4]
3 years ago
9

What is the circumference of this circle? Use π ≈ 3.14. Round your answer to the nearest tenth of a centimeter.

Mathematics
1 answer:
nadezda [96]3 years ago
8 0
We need to now the diameter or radius to find out the circumference.

R times 2 then multiply the product with 3.14
             or
D times 3.14

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Can someone helppp me
stiks02 [169]

Step-by-step explanation:

To find the Circumference of a triangle you use the formula C= 2(pi)r

in both of the problems you have the radius(r) and you plug the #'s in and solve

(pi)= 3.14...

#1.

2(pi)14.5

28(pi)

C= 87.92

#2.

2(pi)9.5

19(pi)

C= 56.66

6 0
2 years ago
Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, what perce
lozanna [386]

At the end of three days,  72.9% of the original amount of liquid remains in Kyle's container .

<u>Step-by-step explanation:</u>

Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:

Let's suppose initially we have 100% of liquid present so ,

<u>At day 1:</u>

10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :

⇒ 100- \frac{100(10)}{100}

⇒ 100-10

⇒ 90%

<u>At day 2:</u>

10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :

⇒ 90- \frac{90(10)}{100}

⇒ 90-9

⇒ 81%

<u>At day 3:</u>

10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :

⇒ 81- \frac{81(10)}{100}

⇒ 81-8.1

⇒ 72.9%

Therefore , At the end of three days,  72.9% of the original amount of liquid remains in Kyle's container .

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3 years ago
In trapezoid EFGH, m∠HEF=(4x2+16)∘ and m∠GFE=(5x2+12)∘. Find the value of x so that EFGH is isosceles. HELP PLEASE!!
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Answer:

The answer would be B if im wrong SORRY ;)\beta\beta \beta \beta \beta \beta \beta \beta \beta \beta \beta \beta \beta \beta \beta

Step-by-step explanation:


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Construct a right triangle whose perimeter is equal to 10cm and one acute angle is 60°
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How can we help you with this?
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