Question

Find the square of (4x – 6y3)2

Answer 1

(4x - 6y³)²
(4x - 6y³)(4x - 6y³)
4x(4x - 6y³) - 6y³(4x - 6y³)
4x(4x) - 4x(6y³) - 6y³(4x) + 6y³(6y³)
16x² - 24xy³ - 24xy³ + 36y⁶
16x² - 48xy³ + 36y⁶

Answer 2

Answer:

$16x^{4} -48xy^{3} +36y^{6}$

Step-by-step explanation:

The given term is :

$(4x-6y^{3} )^{2}$

We can also write this as :

$(4x-6y^{3} )$$(4x-6y^{3} )$

We will use the formula : $(a-b)^{2} =a^{2} -2ab+b^{2}$

We can assume a = 4x

b = $6y^{3}$

So, the answer we get by applying formula is :

$(4x)^{2} -2(4x)(6y^{3} )+(6y^{3})^{2}$

=$16x^{2} -48xy^{3} +36y^{6}$