All categories

3 years ago

What is the answer to this?

Mathematics

1 answer:

konstantin123 [22]3 years ago

3 0

Answer:

$\huge\boxed{-6}$

Step-by-step explanation:

Since we know the values of a, b, and c, we can substitute them into our expression and get the value.

$-2b + | -3c + a |\\\\-2(6) + |-3(-3) + -3 |$

A negative multiplied by a negative gets us a positive.

$-2(6) + |9 + -3 |$

Adding a negative is the same as subtracting a positive.

$-2(6) + |9 -3 |\\-2(6) + 6$

$-2 \cdot 6 = -12\\\\-12+6\\\\-6$

Hope this helped!

You might be interested in

If a = 7, what is the value of the expression 2(a + 8)?

raketka [301]

Answer:

Step-by-step explanation:

Substitute X with 7 since X=7 so 2(7+8). Follow order of operations and 7+8=15 and the multiply 15 by 2 to get your final answer 30.

3 0

3 years ago

Julie was a lifeguard during the summer. She earned a total of $2,176. She was paid $68 per day she worked. How many days did Ju

creativ13 [48]

Answer:

Step-by-step explanation:

To answer this question, you have to divide 2,176 by 68.

7 0

3 years ago

Read 2 more answers

Hey, I'm not sure if I'm wrong or not but wouldn't the answer be c divided by pi? or c/pi

dedylja [7]

Answer:

You are correct

It is C divided by PI

Step-by-step explanation:

c=pi x D

Using substitution method replace letters with numbers

12(c)=3(pi) x 4(d)

we want 4(d) the subject of the formula

4(d)=

12/3 =4

so it is 4(d)=12(c)/3(pi)

so D=C/PI

8 0

3 years ago

Find all zeros of f(x)=x^4-3x^3+6x^2+2x-60 given that 1+3i is a zero of f(x)

Triss [41]

Answer:

The roots of f(x) are: -2, 3, (1+3i) and (1-3i)

Step-by-step explanation:

We are given an expression:

$f(x)=x^4-3x^3+6x^2+2x-60$

(1+3i) is a root of f(x)

We have to find the remaining roots of f(x).

Since, (1+3i) is a root of f(x),

$x-(1+3i)$

is a factor of given expression.

Now, we check if (1 - 3i) is a root of given function.

$f(x)=x^4-3x^3+6x^2+2x-60\\f(1-3i)=(1-3i)^4-3(1-3i)^3+6(1-3i)^2+2(1-3i)-60\\= (28+96i)-3(-26+18i)+6(-8-6i)+2(1-3i)-60 = 0$

Thus, (1-3i) is also a root of given function.

Since, (1-3i) is a root of f(x),

$x-(1-3i)$

is a factor of given expression.

Thus, we can write:

$(x-(1+3i))(x-(1-3i))\text{ is a factor of f(x)}\\x^2-x(1-3i)+x(1+3i)+(1-3i)(1+3i)\text{ is a factor of f(x)}\\x^2-2x+10\text{ is a factor of f(x)}$

Dividing f(x) by above expression:

$\displaystyle\frac{x^4-3x^3+6x^2+2x-60}{x^2-2x+10} = x^2-x-6$

To find the root, we equate it to zero:

$x^2-x-6 = 0\\x^2 - 3x+2x-6=0\\x(x-3)+2(x-3)=0\\(x+2)(x-3) = 0\\x = -2, x = 3$

Thus, the roots of f(x) are: -2, 3, (1+3i) and (1-3i)

4 0

4 years ago

Only number 7 please, and the expression

spin [16.1K]

Answer:

8n, 40 miles in 5 weeks.

Step-by-step explanation:

given that nate runs 8 miles each week.

Hence in n weeks, he will run

8 miles per week x n weeks

= 8n miles

in 5 weeks, n = 5.

Substituting this into the expression,

8(5) = 40 miles

3 0

3 years ago