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kotegsom [21]
3 years ago
6

The dotted lines show how to cut the pie. Identify m∠LPM.

Mathematics
2 answers:
Mademuasel [1]3 years ago
8 0

Answer:

60

Step-by-step explanation:

\frac{1}{2} 80   40\\

\frac{1}{2} 40  20

LKM=20

40+20+mLPK=180

LPK=120

120+LPM=180

LPM=60

allsm [11]3 years ago
4 0
Due to the cause it would end up being the second option
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The area of a rectangular front yard is, 180 square feet find the length of the front yard if the width is 15 feet
VMariaS [17]
Area = length x width
180 = L x 15
L = 180/15
Length = 12 feet
6 0
2 years ago
What is an equation of the line that passes through the points (0,-5) and (-6,0)?
charle [14.2K]

Answer:

y=-5/6x-5

Step-by-step explanation:

0-(-5)/-6-0

-5/6 slope

y-(-5)=-5/6(x-0)

y+5=-5/6x

y=-5/6x-5

8 0
2 years ago
A rectangular yard is 20 feet by 15 feet. The yard Is covered with grass except for an 8.5 feet. Square flower garden. How much
stich3 [128]

Answer: 227.75\ ft^2

Step-by-step explanation:

<h3> The complete exercise is: "A rectangular yard is 20 ft by 15 ft. The yard is cover with grass except for 8.5 feet square flower garden. How much grass is in the yard?"</h3><h3 />

The area of a rectangle can be calculated with the following formula:

A=lw

Where "l" is the lenght of the rectangle and "w" is the width.

Based on the data given in the exercise, you can identify tha the length and the width of the rectangular yard are:

l=20\ ft\\\\w=15\ ft

Then, you can substitute these values into the formula and then evaluate in order to find the area of the entire yard:

A_y=(20\ ft)(15\ ft)=\\\\A_y=300\ ft^2

The area of the flower garden which is an square, can be calculated with this formula:

A=s^2

Where "s" is the side length.

 In this case you know that:

s=8.5\ ft

Then the area of the flower garden is:

A_g=(8.5\ ft)^2\\\\A_g=72.25\ ft^2

<em> </em>Since this is not covered with grass, you need to subtract both areas calculated above in order to find the surface covered with grass in the yard.

This is:

A_g=300\ ft^2-72.25\ ft^2\\\\A_g=227.75\ ft^2

4 0
3 years ago
Assuming the trunk is at least 96 inches deep, can the TV fit into the trunk of<br> the car?
marissa [1.9K]

Answer:

yes it can fit

Step-by-step explanation:

the tv is less than 96 inches tall

7 0
3 years ago
Can someone plz help me! I’ve been trying to figure it but I just can’t
VMariaS [17]

Answer:

Step-by-step explanation:

I'll walk you through how to get the answers, but I'm not sure what your drop downs there are asking for.  Maybe once you see the answers, you can figure out how to get the drop downs chosen correctly.

For your quadratic function, the h on the far left is how high the ball is after it is kicked and some amount of time has gone by, the -16t-squared part is the pull of gravity in feet per sec per sec, the 55t is the vertical velocity, and the 1 means that the ball was kicked when it was 1 foot off the ground. If we want to find when ("when" is a time measure) the ball was 45 feet off the ground, we sub in 45 for the h on the far left. Remember that that h is how high the ball is off the ground after it is kicked and some time has gone by. When we sub in 45 for that h, we will solve for t by factoring, to see at what times the ball is 45 feet from the ground.

It would be best to set up the equation and then plug it into the quadratic formula. Subbing in 45 for h gives us:

45=-16t^2+55t+1 and we get everything on one side of the equals sign and set the quadratic equal to 0, giving us:

-16t^2+55t-44=0 and then plug it into the quadratic formula with a = -16, b = 55, and c = -44:

t=\frac{-55+/-\sqrt{55^2-4(-16)(-44)} }{2(-16)}  and we'll simplify that a little at a time:

t=\frac{-55+/-\sqrt{3025-2816} }{-32}  and

t=\frac{-55+/-\sqrt{209} }{-32} giving us 2 solutions:

t=\frac{-55+14.45683229}{-32}=1.2669 sec and

t=\frac{-55-14.45683229}{-32}=2.1705 sec

Let's interpret these solutions. When the ball is kicked up into the air, it experiences parabolic travel. It goes up to a certain max height until gravity wins and the ball comes back down to the ground. Everything thrown up into the air experiences parabolic (or projectile) motion (because gravity affects everything!). So the ball with reach a max height of some number of feet (you could find that out if you needed to, but we'll let that one go for now since this isn't physics class!) before it comes back down.  On its way up to that max height, it will pass the 45 foot mark, and when it's coming back down, it will pass it again. The time that it passes the 45 foot mark going up is 1.2669 seconds after it is kicked. Then it goes up as high as it's going to and comes back down, passing the 45 foot mark on the way back down, at 2.1705 seconds after it was kicked.

However you need to use that interpretation to pick the correct drop-down answer is up to you. Much luck with your quadratics!! They're very important; you haven't seen the last of them by far!

5 0
3 years ago
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