Answer:
Wyzant
Question
Flying against the wind, an airplane travels 4200 km in 7 hours. Flying with the wind, the same plane travels 4000 km in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 1 vote
Let Va = the velocity of the airplane Let Vw = the velocity of the wind When flying with the wind: (Va+Vw)*(4 hours) = 4000 4Va + 4Vw = 4000 4Vw = 4000 - 4Va Vw = 1000 - Va When flying against the wind: (Va-Vw)*(7 hours) = 4200 km7Va - 7Vw = 4200 Substitute 1000-Va for Vw and solve for Va: 7Va - 7(1000-Va) = 4200 7Va -7000 + 7Va = 4200 14Va = 11200 Va = 800 km/hr Rate of wind: Vw = 1000 - Va = 1000 - 800 = 200 km/hour
More
Socratic
Question
Flying against the wind, an airplane travels 4500 in 5 hours. Flying with the wind, the same plane travels 4640 in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 0 votes
The speed of plane in still air is 1030 km/hr and wind
Step-by-step explanation:
Answer:
(a) h(x) = 1/2x -1/2
Step-by-step explanation:
The inverse of the function y = f(x) is found by solving x = f(y).
__
<h3>setup</h3>
x = f(y)
x = 2y +1 . . . . . . use the definition of f(x)
<h3>solution</h3>
x -1 = 2y . . . . . subtract 1
(x -1)/2 = y . . . . divide by 2
y = 1/2x -1/2 . . . . eliminate parentheses
h(x) = 1/2x -1/2 . . . write in functional form
The inverse of f(x) = 2x+1 is ...
h(x) = 1/2x -1/2
Answer:
-4
Step-by-step explanation:
1. Always start with the parenthesis. (26/13) = 2
2. Then multiply. 2*-7 = -14
3. After, you add 14 to your precious answer (-14) then subtract 4.
-14 + 14 = 0 - 4 = -4
Answer:
-2
Step-by-step explanation:
Hope it helps
The increase will be the original price x the increase rate.
15649 x 0.035 = $547.72
The new price would be original price + increase
15649 + 547.72 = $16,196.72
