Missing part of the question
Determine the number of handshakes, i, that will occur for each number of people, n, in a particular room. (people)
Answer:
Step-by-step explanation:
Given
For 5 people
Using the given instance of 5 people, the number of handshakes can be represented as:
The above sequence is an arithmetic sequence and the total number of handshakes is the sum of n terms of the sequence.
Where
--- The first term
--- The last term
So:
The lease common multiple of the set of numbers is 108.
108/4=27.
108/27=4.
108/12=9.
Answer:
3 ways
Step-by-step explanation:
Since 6 will remain constant throughout the testing, we just need to find all prime numbers 1-6.
1 - is not prime nor composite
2 - is prime
3 - is prime
4 - 2x2=4, so composite
5 - is prime
6 - 2x3=6, so composite
Therefore, 2, 3, and 5 are prime numbers, and there are 3 of them.
10
Because if you do 5•2 you get 10
More in depth explanation:
Though there are 25 possible configurations the question asks for two different toppings together. It also asks for unique combinations. So AB and BA are the same combination in this context. The only unique possibilities are
AB
AC
AD
AE
BC
BD
BE
CD
CE
DE
It is easy to simplify this into 5•2 for this situation. And if the question asked for three toppings you would do 5•3.
However if the question asked for the configurations for two toppings then you would do 5•5 and if it asked for the configurations of 3 toppings you would do 5•5•5
387/100
p/q formula
The theorem states that each rational solution x = p⁄q, written in lowest terms so that p and q are relatively prime, satisfies: p is an integer factor of the constant term a0, and.
