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IrinaK [193]
4 years ago
14

In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys

tem if the initial energy was 2000 j? 1. write the equation 2.list out your known variables 3.plug the numbers into the equations 4.Solve 5.write your solution statement that includes initial energy and final
Physics
1 answer:
son4ous [18]4 years ago
3 0

Answer:

2500 J

Explanation:

We can solve the problem by using the first law of thermodynamics:

\Delta U =U_f - U_i =Q-W

where

Uf is the final internal energy of the system

Ui is the initial internal energy

Q is the heat added to the system

W is the work done by the system

In this problem, we have:

Q = +1000 J (heat that enters the system)

W = +500 J (work done by the system)

Ui = 2000 J (initial internal energy)

Using these numbers, we can re-arrange the equation to calculate the final internal energy:

U_f = U_i + Q-W=2000 J+1000 J-500 J=2500 J

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Jupiter is 317 times more massive than the Earth. An astronaut on Jupiter would _____. weigh less than on Earth weigh more than
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Since "you will weigh more on jupiter" isn't an option, your answer is  <u>B."weigh more than on Earth"</u> <em>btw ik this is a late answer but for the people out there still searching for an answer hope this helps!</em>

8 0
3 years ago
1 Item 1 Item 1 1.25 points circular ceramic plate that can be modeled as a blackbody is being heated by an electrical heater. T
Elena L [17]

Answer:

174.85 W

Explanation:

Area of plate = 3.14 x (15x 10⁻²)²

= 706.5 x 10⁻⁴ m²

heat being radiated by convection = 12 x 706.5 x 10⁻⁴ ( 180 - 15 )

= 139.88 W. This energy needs to be fed by heat source to maintain a constant temperature of 180 degree.

If power of electric source is P

P x .8 = 139.88

P = 139.88 / .8

= 174.85 W

6 0
3 years ago
A book has a mass of 50 grams and an acceleration of 5 m/s/s. What is the force on the book?
Ivan

Answer:

250 newtons i belive.

Explanation:

8 0
3 years ago
What could be used as another word for electrical potential
tekilochka [14]

Answer:

hey mate

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Explanation:

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5 0
3 years ago
Read 2 more answers
A 37.5 kg box initially at rest is pushed 4.05 m along a rough, horizontal floor with a constant applied horizontal force of 150
vodomira [7]

Answer:

a) 607.5 J

b) 160.531875 J

c)  0 J

d)  0 J

e) 2.925 m\s

Explanation:

The given data :-

  • Mass of the box ( m ) = 37.5 kg.
  • Displacement made by box ( x ) = 4.05 m.
  • Horizontal force ( F ) = 150 N.
  • The co-efficient of friction between box and floor ( μ ) = 0.3
  • Gravitational force ( N ) = m × g = 37.5 × 9.81 = 367.875

Solution:-

a) The work done by applied force ( W )

W = force applied × displacement = 150 × 4.05 = 607.5 J

b)  The increase in internal energy in the box-floor system due to friction.

Frictional force ( f ) = μ × N = 0.3 × 367.875 = 110.3625 N

Change in internal energy = change in kinetic energy.

ΔU = ( K.E )₂ - ( K.E )₁

Since the initial velocity is zero so the  ( K.E )₁ = 0  

ΔU = ( K.E )₂ = ( F - f ) × ( x ) = ( 150 - 110.3625 ) × 4.05 = 160.531875 J

c) The work done by the normal force .

Displacement of box vertically = 0

W = force applied × displacement = 367.875 × 0 = 0 J

d)  The work done by the gravitational force.

Displacement of box vertically = 0

W = force applied × displacement = 367.875 × 0 = 0 J

e) The change in kinetic energy of the box

( K.E )₂ - ( K.E )₁ = ( K.E )₂ - 0 = ( F - f ) × ( x ) = ( 150 - 110.3625 ) × 4.05 = 160.531875 J

f) The final speed of the box

( K.E )₂ = 160.531875 J = 0.5 × 37.5 × v²

v² = 8.56

v = 2.925 m\s.

5 0
4 years ago
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