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Lady_Fox [76]
3 years ago
15

Nate the Skate was an avid physics student whose main non-physics interest in life was high-speed skateboarding. In particular,

Nate would often don a protective suit of Bounce-Tex, which he invented, and after working up a high speed on his skateboard, would collide with some object. In this way, he got a gut feel for the physical properties of collisions and succeeded in combining his two passions. On one occasion, the Skate, with a mass of 129 kg, including his armor, hurled himself against an 831 kg stationary statue of Isaac Newton in a perfectly elastic linear collision. As a result, Isaac started moving at 1.29 m/s and Nate bounced backward. What were Nate's speeds immediately before and after the collision? Ignore friction with the ground. Choose the correct option;
(a) before collision: 4.8m/sAfter Collision: 1.29m/s
(b) before collision: 2.8m/sAfter Collision: 2.29m/s
(c) before collision: 3.8m/sAfter Collision: 3.29m/s
(d) before collision: 5.8m/sAfter Collision: 1.29m/s
Physics
1 answer:
Ivenika [448]3 years ago
4 0

Answer:

v_{1i} = 4.8 m/s

v_{1f} = 3.51 m/s

Explanation:

Since the collision is perfectly elastic collision so here we can use momentum conservation

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

so we will have

129 v_{1i} + 0 = 129(-v_{1f}) + 831(1.29)

v_{1i} + v_{1f} = 8.31

also by elastic collision property we will have

1.29 + v_{1f} = v_{1i}

now from above two equations we have

v_{1i} = 4.8 m/s

v_{1f} = 3.51 m/s

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A 615.00 kg race car is uniformly traveling around a circular race track. It takes the race car 20.00 seconds to do one lap arou
koban [17]

Answer:

The value is  f  =  0.05 \ Hz

Explanation:

From the question we are told that

     The mass of the car is  m  =  615 \  kg

      The period of the circular motion is  T  =  20 \  s

      The radius  is r =  80 \  m/s

Generally the frequency of the circular motion is  

       f  =   \frac{1}{T }

=>    f  =   \frac{1}{ 20  }

=>    f  =  0.05 \ Hz

3 0
3 years ago
Why do you think we cannot use a common fuel like diesel or gasoline for space travel ?
Ede4ka [16]

Answer:

Explanation:

it take oxygen in the atmosphere to burn it... in space there isn't any air  :0

5 0
3 years ago
Mike is standing on the roof of a building looking at the roof of the neighboring building that is 15 meters away and 10 meters
amid [387]

Answer:

Part a)

t = 1.65 s

Part b)

x = 40.4 m

Since the distance of other building is 15 m so YES it can make it to other building

Part c)

v = 27.3 m/s

direction of velocity is given as

[tex]\theta = 26.35 degree

Explanation:

Part a)

acceleration due to gravity on this planet is 3/4 times the gravity on earth

So the acceleration due to gravity on this new planet is given as

a = \frac{3}{4}(9.81)

a = 7.36 m/s^2

now the vertical displacement covered by the canister is given as

y = 10 m

now by kinematics we have

y = \frac{1}{2}gt^2

10 = \frac{1}{2}(7.36)t^2

t = 1.65 s

Part b)

Horizontal speed of the canister is given as

v_x = 24.5 m/s

now the distance moved by it

x = v_x t

x = 24.5 (1.65)

x = 40.4 m

Since the distance of other building is 15 m so YES it can make it to other building

Part c)

Final velocity in X direction will remains the same

v_x = 24.5 m/s

final velocity in Y direction

v_y = v_i + at

v_y = 0 + (7.36)(1.65)

v_y = 12.14 m/s

now magnitude of velocity is given as

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{24.5^2 + 12.14^2}

v = 27.3 m/s

direction of velocity is given as

\theta = tan^{-1}\frac{v_y}{v_x}

\theta = tan^{-1}\frac{12.14}{24.5}

[tex]\theta = 26.35 degree

6 0
3 years ago
In operant conditioning, many complex behaviors are learned through shaping. T or F
Snezhnost [94]

Answer:  

true

Explanation:

8 0
3 years ago
A woman living in a third-story apartment is moving out. Rather than carrying everything down the stairs, she decides to pack he
Flura [38]

Answer:

T = 480.2N

Explanation:

In order to find the required force, you take into account that the sum of forces must be equal to zero if the object has a constant speed.

The forces on the boxes are:

T-Mg=0      (1)

T: tension of the rope

M: mass of the boxes 0= 49kg

g: gravitational acceleration = 9.8m/s^2

The pulley is frictionless, then, you can assume that the tension of the rope T, is equal to the force that the woman makes.

By using the equation (1) you obtain:

T=Mg=(49kg)(9.8m/s^2)=480.2N

The woman needs to pull the rope at 480.2N

8 0
3 years ago
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