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Verdich [7]
3 years ago
11

Find the resultant of two forces of 4.0N and 6.0N acting at an angle of 160° to each other.

Physics
1 answer:
hichkok12 [17]3 years ago
6 0

\star\sf \overrightarrow{A}=4N

\star\sf\overrightarrow{B}=6N

Angle=160

\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\theta}}

\\ \sf\longmapsto R=\sqrt{4^2+6^2+2(4)(6)cos160}

\\ \sf\longmapsto R=\sqrt{16+36+48(-0.93)}

\\ \sf\longmapsto R=\sqrt{52-44.6}

\\ \sf\longmapsto R=\sqrt{7.4}

\\ \sf\longmapsto R=2.7N

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