Question

Find the resultant of two forces of 4.0N and 6.0N acting at an angle of 160° to each other.

Answer 1

$\star\sf \overrightarrow{A}=4N$

$\star\sf\overrightarrow{B}=6N$

Angle=160

$\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\theta}}$

$\\ \sf\longmapsto R=\sqrt{4^2+6^2+2(4)(6)cos160}$

$\\ \sf\longmapsto R=\sqrt{16+36+48(-0.93)}$

$\\ \sf\longmapsto R=\sqrt{52-44.6}$

$\\ \sf\longmapsto R=\sqrt{7.4}$

$\\ \sf\longmapsto R=2.7N$