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Orlov [11]
3 years ago
14

Pls help asap!!! i need help

Physics
2 answers:
Mkey [24]3 years ago
5 0
Its the second one [b]
Murljashka [212]3 years ago
4 0

Answer:

frost

Explanation:

Hope this helps. :)

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A drag racer starts from the rest and accelerates at 7.4m/s^2.how far will he travel in 2.0 seconds?
Vesna [10]

Answer:

14.8 m

Explanation:

S= ut + \frac{1}{2}at^{2}

where u = initial velocity

S= (0 \frac{m}{s})(2s) + \frac{1}{2}(7.4\frac{m}{s^{2} })(2s^{2})

S=  \frac{1}{2}(7.4\frac{m}{s^{2} })(2s^{2})

S=14.8 m

8 0
3 years ago
Taking test, need physics help<br> ASAP please!
Anuta_ua [19.1K]

Answer:

im pretty sure its c the third answer i got that one right

Explanation:

your welcome :)

8 0
2 years ago
In transduction, the cochlea is part of this structure:
anyanavicka [17]

Answer:

wats up

Explanation:

8 0
3 years ago
What is the main reason for using a data table for collecting data?
Luba_88 [7]

Answer:

to make calculation more easy to get

Explanation:

if you are using chart or calculate Thermodynamic problems you will not never solve this problem with out using data table for thermodynamic

7 0
3 years ago
A train at rest emits a sound at a frequency of 1057 Hz. An observer in a car travels away from the sound source at a speed of 2
il63 [147K]

Answer:

993.52 Hz

Explanation:

The frequency of sound emitted by the stationery train is 1057 Hz.

The car travels away from the train at 20.6 m/s.

The frequency the observer hears is given by the formula:

f_o = \frac{v - v_o}{v}f

where v = velocity of sound = 343 m/s

vo = velocity of observer

f = frequency from source

This phenomenon is known as Doppler's effect.

Therefore:

f_o = \frac{343 - 20.6}{343} * 1057\\ \\f_o = 322.4 / 343 * 1057\\\\f_o = 993.52 Hz

The frequency heard by the observer is 993.52 Hz.

4 0
4 years ago
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