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geniusboy [140]
4 years ago
5

When an object is turning around, is it also at rest at the point?

Physics
2 answers:
Ganezh [65]4 years ago
8 0

Answer:

yes

Explanation:

Depolarization

AysviL [449]4 years ago
8 0
When an object changes direction, it’s velocity goes to 0 at that point. So the object will also be considered at rest.
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Ball A (7kg) and ball B (3kg) hit each other in a perfectly elastic collision. If ball A has an initial velocity of 12 m/s and b
dusya [7]

Explanation:

Mass of ball A, m_A=7\ kg

Mass of ball B, m_B=3\ kg

Initial velocity of ball A, u_A=12\ m/s

Initial velocity of ball B, u_B=-1\ m/s

We need to find the final velocity of each ball. For a perfectly elastic collision, the coefficient of restitution is equal to 1. It is given by :

e=\dfrac{v_B-v_A}{u_A-u_B}

v_A\ and\ v_B are final velocities of ball A and B

1=\dfrac{v_B-v_A}{13}

v_B-v_A=13...........(1)

Using the conservation of linear momentum as :

m_Au_A+m_Bu_B=m_Av_A+m_Bu_B

7(12)+3(-1)=7v_A+3u_B

7v_A+3u_B=81..............(2)

On solving equation (1) and (2) using calculator we get :

v_A=4.2\ m/s

v_B=17.2\ m/s

So, the final velocities of ball A and B are 4.2 m/s and 17.2 m/s. Hence, this is the required solution.

4 0
3 years ago
A 2.5-kg rock is dropped off a 32-m cliff and hits a spring, compressing it 57 cm. What is the spring constant? Round your answe
n200080 [17]

Answer: 4800 N/m

Explanation:

Given

mass of rock m=2.5\ kg

Height of cliff h=32\ m

compression in the spring x=57\ cm

Here, potential energy is converted into kinetic energy which in turn converts to elastic potential energy of the spring

\Rightarrow mgh=\dfrac{1}{2}kx^2\\\\\Rightarrow k=\dfrac{2mgh}{x^2}\\\\\Rightarrow k=\dfrac{1568}{0.3249}\\\\\Rightarrow k=4826.100\approx 4800\ N/m

6 0
3 years ago
Read 2 more answers
Mr. huff and puff is getting ready to blow up a pool float because he can't find the air pump. he takes a big breath in after ex
andrezito [222]
It’s just the second time my boy
4 0
2 years ago
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Suppose you discover that the circuit you are testing in the lab does not function correctly due to a hold time violation. What
iVinArrow [24]

Answer:

Explanation:

Hold time is referred as the minimum time after active edge  of clock after which data must be stable so hold violation will cause the incorrect data to be added.

In such circuit the first thing that can be done to fix this will be :

- Reset the clock to the start/endpoint to make end point clock arrive earlier.

- Insert a buffer chain to increase the propagation time.

- Add delays

4 0
3 years ago
A bus is moving at a constant speed of 40 m/s. How many hours will it takes to travel 260 miles?
lawyer [7]

Explanation:

1 mile = 1609m

Distance=260 miles= 418340 m

Speed= 40 m/s

Time = distance/speed

= 418340/40

=10458.5 seconds

= 2.9 hours

8 0
3 years ago
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