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3 years ago

When an object is turning around, is it also at rest at the point?

Physics

2 answers:

Ganezh [65]3 years ago

8 0

Answer:

yes

Explanation:

Depolarization

AysviL [449]3 years ago

8 0

When an object changes direction, it’s velocity goes to 0 at that point. So the object will also be considered at rest.

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You are exploring a distant planet. When your spaceship is in a circular orbit at a distance of 630 km above the planet's surfac

Anarel [89]

Answer:

$R = 24.3 m$

Explanation:

As we know that the orbital speed is given as

$v = \sqrt{\frac{GM}{R + h}}$

here we know that

v = 5500 m/s

$R = 4.48 \times 10^6 m$

$h = 630 km$

now we have

$5500 = \sqrt{\frac{(6.6 \times 10^{-11})M}{4.48 \times 10^6 + 6.30\times 10^5}}$

$M = 2.34 \times 10^24 kg$

now acceleration due to gravity of planet is given as

$a = \frac{GM}{R^2}$

$a = \frac{(6.6 \times 10^{-11})(2.34 \times 10^{24})}{(4.48\times 10^6)^2}$

$a = 7.7 m/s^2$

now range of the projectile on the surface of planet is given as

$R = \frac{v^2 sin2\theta}{g}$

$R = \frac{14.6^2 sin(2\times 30.8)}{7.7}$

$R = 24.3 m$

3 0

3 years ago

A student makes the following statement

Aliun [14]

Answer:

The current is not used up. The electrons flow through the entire circuit and this travel is the current. They flow until they are not charged anymore. That is also why the circuit must be closed or else electrons would escape not just light it up for a second then go out.

Explanation:

8 0

3 years ago

Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. His

Ludmilka [50]

Answer:

12 m/s west

Explanation:

4 0

2 years ago

Read 2 more answers

The three types of nuclear radiation<br>

Eva8 [605]

The three types are alpha beta and gamma

6 0

3 years ago

Assume a solar cell would produce a current of 500mA and 3 V. What is the power of this solar cell?

defon

Answer:

the power of the solar cell is 1.5 watts

Explanation:

Recall that power is defined as the product of the voltage (V) times the running current (I): Power = V * I.

The only thing we have to take care of before actually performing the operation, is to convert milliamps into Amps, so our answer comes directly in the appropriate units (Watts). 500 mAmps can be written as 0.5 Amps, then, the product becomes:

Power = V * I = 3 V * 0.5 Amps = 1.5 watts

8 0

2 years ago