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Alexxandr [17]
3 years ago
7

A function is expressed by the equation y=0.3x−6. For what value of the independent variable will the value of the function be e

qual to −6; −3; 0?
Mathematics
1 answer:
Anna11 [10]3 years ago
7 0

Answer:

0; 10; 20

Step-by-step explanation:

x is the independent variable

y is the dependent variable

y is dependent on x

a) For what value of the independent variable will the value of the function be equal to −6

y=0.3x−6

-6 = 0.3x-6

0=0.3x

x = 0

Therefore, if the independent variable is 0, the value of the function will be -6.

b) For what value of the independent variable will the value of the function be equal to −3

y=0.3x−6

-3 = 0.3x-6

0.3x = -3+6

0.3x = 3

x = 3/0.3

x = 10

Therefore, if the independent variable is 10, the value of the function will be -3.

c) For what value of the independent variable will the value of the function be equal to 0.

y=0.3x−6

0=0.3x-6

6 = 0.3x

x = 6/0.3

x = 20

Therefore, if the independent variable is 20, the value of the function will be 0.

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Answer:

2.50

Step-by-step explanation:

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Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i
steposvetlana [31]

Answer:

The distance between the two given complex numbers = 9

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i):</em></u>-

Given  Z₁ = 9 - 9 i    and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A =  Z₁ = x₁ +i y₁ = 9 - 9 i and

    B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

     (x₂, y₂) = (10, -9)

<u>Step(ii)</u>:-

<em>The distance between the two points are </em>

    A B   =   \sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2}    }

    A B =   \sqrt{(10 - 1)^{2}+(-9 - (-9))^{2}    }

   AB   = \sqrt{(9)^{2} +(-9+9)^{2} }

 <em> AB    =  √81 = 9</em>

<u><em>Conclusion:-</em></u>

The distance between the two given complex numbers = 9

<u><em></em></u>

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Step-by-step explanation:

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