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3 years ago

The formula for the bowline of a sphere is V=4/3πr^3. solve for r

Mathematics

1 answer:

Tpy6a [65]3 years ago

5 0

Answer:

$r=\sqrt[3]{\frac{3V}{4\pi}}$

Step-by-step explanation:

$v= \frac{4}{3} \pi r^3$

We need to isolate 'r'

To isolate 'r' , first multiply by 3 on both sides

$3v=4* \pi r^3$

divide by 4pi on both sides

$\frac{3V}{4\pi} = r^3$

Take cube root on both sides

$\sqrt[3]{\frac{3V}{4\pi}}= r$

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5x – 12y – 17 = 0<br> 1*9(x + 2) - (y + 1) + 3 = 0

valentina_108 [34]

Answer: $x=\frac{12y+17}{5}$

$y=\frac{-5x+17}{-12}$

$x=\frac{y-20}{9}$

y=9x+20

Step-by-step explanation:

5x-12y-17=0 (plus 17 from both sides)

5x-12y=17 (plus 12y from both sides)

5x=12y+17 (divide 5 from everything)

$x=\frac{12y+17}{5}$

5x-12y-17=0 (plus 17 from both sides)

5x-12y=17 (minus 5x from both sides)

-12y=-5x+17 (divide everything by -12)

$y=\frac{-5x+17}{-12}$

1*9(x+2)-(y+1)+3=0 (distribute 9 to x and to 2) (distribute -1 to y and to 1)

1*9x+18-y-1+3=0 (times 9x by 1)

9x+18-y-1+3=0 (combine like terms)

9x-y+20=0 (minus 20 from both sides)

9x-y=-20 (plus y to both sides)

9x=y-20 (divide 9 from both sides)

$x=\frac{y-20}{9}$

1*9(x+2)-(y+1)+3=0 (distribute 9 to x and to 2) (distribute -1 to y and to 1)

1*9x+18-y-1+3=0 (times 9x by 1)

9x+18-y-1+3=0 (combine like terms)

9x-y+20=0 (minus 20 from both sides)

9x-y=-20 (minus 9x from both sides)

-y=-9x-20 (divide -1 from everything)

y=9x+20

3 0

3 years ago

Match with correct description

fgiga [73]

First one: If the leading coeff. is negative, the graph begins in Quadrant III and ends in Quadrant IV. It's an even function. The fourth graph represents it.

If the leading coeff. is positive, but everything else remains the same, the graph opens upward, beginning in Q II and ending in Q I.

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3 years ago

Evaluate: 16 - 2+3 - 4

natulia [17]

Answer: 13

Step-by-step explanation:

Following order of operations:

16-2+3-4

14+3-4

17-4

8 0

3 years ago

Read 2 more answers

Two number cubes are rolled.

hichkok12 [17]

Answer:

When two number cubes are rolled,

Sample space= Total Possible outcome {11,22,33,44,55,66,12,21,13,31,14,41,15,51,16,61,23,32,24,42,25,52,26,62,34,43,35,53,36,63,45,54,46,64,56,65}=36

Probability of an event = \frac{\text{Total favorable outcome}}{\text{Total possible outcome}}

Sum of 4 is obtained when ={13,31,22}=3

Probability of getting 4 when 2 number cubes are rolled= \frac{3}{36}=\frac{1}{12}

Sum of the numbers is greater than 9= 10, 11,12={55,64,46,56,65,66}=6

Probability of getting(Sum of the numbers is greater than 9)=\frac{6}{36}=\frac{1}{6}

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3 years ago

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Afina-wow [57]

Answer:

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Step-by-step explanation:

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