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nordsb [41]
3 years ago
8

PLEASE ANSWER QUICK 2 MINUTES ON THE TIMER

Mathematics
2 answers:
snow_lady [41]3 years ago
8 0
<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷ Turn into improper fractions:

8/3 + 5/3

Now just add them:

13/3 or 4 1/3

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Mrac [35]3 years ago
8 0

Answer:

You have 5 ¹/₃ cups.

Step-by-step explanation:

If fractions go over the number on the bottom, add 1 to the mixed number and continue adding to the fraction as needed. All you need to know by 2 minutes.

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Even numbers greater than -37 but less than -25
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Answer:

-36, -34, -32, -30, -28, -26

Step-by-step explanation:

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5th grade math. Correct answer will be marked brainliest
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Answer:

3,5

Step-by-step explanation:

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2 years ago
What is the GCF of 44j^5k^4 and 121j^2k^6?
Leviafan [203]

44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\  121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4

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2 years ago
Read 2 more answers
Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
Solve the differentiatial equation: equation it is known that when x = 0, y = 16
Daniel [21]
If you use Y=x+ whatever number you will get your answer
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