In an AP, sum of four consecutive terms is 28 and their sum of their squares is 276. Find the four numbers.

1 answer:

4 0

Four Consecutive terms are written as a-3, a-1, a+1,a+3. So

Sum of Terms : 4a=28
a=7

So the terms are 4,6,8,10

Verification : 4^2+6^2+8^2+10^2
= 216

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