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Lady bird [3.3K]
3 years ago
7

When the football is on its way up, 1. BLANK energy is being transformed into 2. BLANK energy.

Chemistry
2 answers:
weqwewe [10]3 years ago
8 0
When the football is on its way up, Kinetic energy is being transformed into Gravitational Potential energy.
oksian1 [2.3K]3 years ago
6 0
I think it is 1 because as it goes up it loses energy and when it comes down it is gaining that energy back.
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What is the overall reaction order for this rate law: rate = k[A]2[B][C]?
dybincka [34]

Zero order are reactions in which concentration of reactant has NO effect on RATE OF REACTION.


2. First order are reactions in which concentration of one reactant is proportionate to the RATE OF REACTION.

Exp: That means when you increase the concentration of the one reactant, then the rate of reaction will increase by the same degree of extent.


3. Second order are reactions in which concentration of two reactant has an effect on the RATE OF REACTION.


Formula:

1. Zero order Rate = k

2. First order Rate = k(A)^m

3. Second order Rate = k(A)^m(B)^n


where () represents concentration

and equation is mA + nB -> Product.




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3 years ago
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7. What type of water pollution is produced from chemicals used to kill bugs and<br> weeds?
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Answer:

Groundwater pollution

Explanation:

Pesticides, when sprayed on crop plants, are able to flow below the surface of the ground, reaching water-bearing aquifers, thereby contaminating groundwater, making it unsuitable for both human and agricultural uses.

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How does most ocean water return to the ocean in the water cycle?
serious [3.7K]

Explanation:

The correct answer is C.

Through runoff on Earth's surface. Hope this helped!

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Will Mark Brainliest!
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Answer:

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Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

3 0
3 years ago
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