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Lisa [10]
3 years ago
10

-6x - 17 ≥ 8x 25 what is the solution of the inequality

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0
The answer is
x \leq -3
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Need. help please give answer for this if its right ill mark brainiest<br> 2(5x+2)=2x+20
White raven [17]

Answer:

x=2

Step-by-step explanation:

10x+4=2x+20

10x-2x=20-4

8x=16

x=2

8 0
2 years ago
Read 2 more answers
T divided by 5/12 =-3/10<br><br><br> t=____
damaskus [11]

Answer:

Step-by-step explanation:

t ÷ 5/12 = -3/10

t * 12/5 = -5/10

t=\frac{-3*5}{10*12}\\\\t=\frac{-1*1}{2*4}\\\\t=\frac{-1}{8}

6 0
3 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
Earth, Mars, Saturn, Uranus and Neptune revolve around the sun. Earth takes 1 year, Mars 2 years, Saturn 30 years, Uranus 84 yea
Anettt [7]

Answer:

  30 years

Step-by-step explanation:

2 is a factor of 30, so the LCM of 2 and 30 is 30.

Saturn and Mars will appear in the same direction in the night sky every 30 years.

3 0
3 years ago
(Pls help) A pie crust recipe calls for 2 cups of butter for each 3 cups of flour. Ella is making enough
blagie [28]

.6 cups of flour Step-by-step explanation:

4 0
2 years ago
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