Answer:
The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.
Step-by-step explanation:
Given:
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.
The tax of the first city was 6% and the tax of the second city was 10%.
Total hotel tax paid for two cities with $670.
Now, to find the hotel charge in each city before tax.
Let the hotel charge in first city before tax be ![x.](https://tex.z-dn.net/?f=x.)
And the hotel charge in second city before tax be ![y.](https://tex.z-dn.net/?f=y.)
<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>
<em>Thus</em>,
........(1)
<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>
6% of
+ 10% of
= $670.
![\frac{6x}{100} +\frac{10y}{100} =670](https://tex.z-dn.net/?f=%5Cfrac%7B6x%7D%7B100%7D%20%2B%5Cfrac%7B10y%7D%7B100%7D%20%3D670)
![0.06x+0.10y=670](https://tex.z-dn.net/?f=0.06x%2B0.10y%3D670)
Substituting the value of
from equation (1) we get:
![0.06x+0.10(x-1500)=670](https://tex.z-dn.net/?f=0.06x%2B0.10%28x-1500%29%3D670)
![0.06x+0.10x-150=670](https://tex.z-dn.net/?f=0.06x%2B0.10x-150%3D670)
![0.16x-150=670](https://tex.z-dn.net/?f=0.16x-150%3D670)
<em>Adding both sides by 150 we get:</em>
![0.16x=820](https://tex.z-dn.net/?f=0.16x%3D820)
<em>Dividing both sides by 0.16 we get:</em>
![x=5125.](https://tex.z-dn.net/?f=x%3D5125.)
<em>The hotel charge in first city before tax = $5125.</em>
Now, substituting the value of
in equation (1) we get:
![y=x-1500](https://tex.z-dn.net/?f=y%3Dx-1500)
![y=5125-1500](https://tex.z-dn.net/?f=y%3D5125-1500)
![y=3625.](https://tex.z-dn.net/?f=y%3D3625.)
<em>The hotel charge in second city before tax = $3625.</em>
Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.