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Karolina [17]
3 years ago
9

For a given reaction, adding a catalyst increases the rate of the reaction by

Chemistry
2 answers:
Ksju [112]3 years ago
8 0

Answer : Option 2) providing an alternate reaction pathway that has a lower activation energy


Explanation : When a catalyst is added to a chemical reaction it increases the rate of reaction by lowering the energy of activation. It provides an alternate pathway for a reaction to proceed with a lower Ea energy. Usually a catalyst never gets consumed in the reaction process. It will appear in the reaction mechanism steps but not in the overall reaction like reactants and products.

Andrej [43]3 years ago
6 0
The answer is (2) providing an alternate reaction pathway that has a lower activation energy. The lower activation energy will lead to the increase of rate of the reaction.
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Hunter-Best [27]

Answer:

constant

Explanation:

A constant is a number with a fixed value in a specific mathematical context

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Find the kinetic energy of a boy of mass 6.5kg running at a velocity of 6.0m/s​
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Explanation:

Given,

M=6.5kg,velocity(v)=6m/s

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2 years ago
How many liters of 15.0 molar NaOH stock solution will be needed to make 17.5 liters of a 1.4 molar NaOH solution? Show the work
strojnjashka [21]
2.0 L
The key to any dilution calculation is the dilution factor

The dilution factor essentially tells you how concentrated the stock solution was compared with the diluted solution.

In your case, the dilution must take you from a concentrated hydrochloric acid solution of 18.5 M to a diluted solution of 1.5 M, so the dilution factor must be equal to

DF=18.5M1.5M=12.333

So, in order to decrease the concentration of the stock solution by a factor of 12.333, you must increase its volume by a factor of 12.333by adding water.

The volume of the stock solution needed for this dilution will be

DF=VdilutedVstock⇒Vstock=VdilutedDF

Plug in your values to find

Vstock=25.0 L12.333=2.0 L−−−−−

The answer is rounded to two sig figs, the number of significant figures you have for the concentration od the diluted solution.

So, to make 25.0 L of 1.5 M hydrochloric acid solution, take 2.0 L of 18.5 M hydrochloric acid solution and dilute it to a final volume of 25.0 L.

IMPORTANT NOTE! Do not forget that you must always add concentrated acid to water and not the other way around!

In this case, you're working with very concentrated hydrochloric acid, so it would be best to keep the stock solution and the water needed for the dilution in an ice bath before the dilution.

Also, it would be best to perform the dilution in several steps using smaller doses of stock solution. Don't forget to stir as you're adding the acid!

So, to dilute your solution, take several steps to add the concentrated acid solution to enough water to ensure that the final is as close to 25.0 L as possible. If you're still a couple of milliliters short of the target volume, finish the dilution by adding water.

Always remember

Water to concentrated acid →.NO!

Concentrated acid to water →.YES!
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