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8090 [49]
3 years ago
5

Why argon is octent ??​

Chemistry
2 answers:
Ira Lisetskai [31]3 years ago
6 0

Answer:

argon is octet because it has eight electrons in its valence shell

Explanation:

Temka [501]3 years ago
6 0
Octet (eight electrons) in the outer atomic shell makes argon stable and resistant to bonding with other elements.
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The half-life of cobalt-60 is 5.3 years. after __________ years, 1/4 of the original amount of cobalt-60 will remain.
cestrela7 [59]
The  number of  years  required  for 1/4  cobalt-60  to remain   after   decay  is calculated  as follows

  after  one  half life  1/2 of the original  mass isotope  remains

after  another half life 1/4  mass  of  original  mass  remains

therefore  if one  half  life is  5.3   years  then  the  years required

= 2  x 5.3years =  10.6   years
4 0
2 years ago
Read 2 more answers
A hot lump of 30.5 g of iron at an initial temperature of 52.7 °C is placed in 50.0 mL H2O initially at 25.0 °C and allowed to r
slava [35]

Answer:

26.7°C

Explanation:

Using the formula; Q = m × c × ΔT

Where; Q = amount of heat

m = mass

c = specific heat

ΔT = change in temperature

In this question involving iron placed into water, the Qwater = Qiron

For water; m= 50g, c = 4.18 J/g°C, Initial temp= 25°C, final temp=?

For iron; m = 30.5g, c = 0.449J/g°C, Initial temp= 52.7°C, final temp=?

Qwater = -(Qiron)

m × c × ΔT (water) =- {m × c × ΔT (iron)}

50 × 4.18 × (T - 25) = - {30.5 × 0.449 × (T - 52.7)}

209 (T - 25) = - {13.6945 (T - 52.7)}

209T - 5225 = -13.6945T + 721.7

209T + 13.6945T = 5225 + 721.7

222.6945T = 5946.7

T = 5946.7/222.6945

T = 26.7

Hence, the final temperature of water and iron is 26.7°C

8 0
3 years ago
Which of these statements best identifies the particle that is labeled with an X?
kvv77 [185]
It is either a proton or a neutron
4 0
3 years ago
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Name the following alkyne:
Lady bird [3.3K]

Answer:

There isn't any picture for me to see

have a good day :)

Explanation:

3 0
2 years ago
CdF2(s)⇄Cd2+(aq)+2F−(aq)A saturated aqueous solution of CdF2 is prepared. The equilibrium in the solution is represented above.
kupik [55]

Answer:

The correct answer is option a.

Explanation:

CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)

Equilibrium concentration cadmium ions = [Cd^{2+}]=0.0585 M

Equilibrium concentration fluoride ions = [F^{-}]=0.117 M

Molar solubility is the maximum concentration of salt present in water in ionic form beyond that no more salt will exist in its ionic form and will settle down in bottom of the solution.

The molar solubility of the solid cadmium fluoride = 0.0585 M

CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)..[1]

NaF(s)\rightleftharpoons Na^{+}(aq)+F^-(aq)

Due to addition of sodium fluoride will increase concentration of fluoride in the solution.And due to common ion effect the equilibrium will shift in backward direction in [1], that is precipitation of more cadmium fluoride.

Hence, decrease in solubility will be observed.

8 0
2 years ago
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