Answer:
ΔPTS≅ΔRTA by AAS axiom of congruency
Step-by-step explanation:
Consider ΔPQA and ΔRQS
∠PQA=∠RQS (Vertically Opposite Angles)
∠QAP=∠QSR (Complementary of two equal angles, ∠RAT and∠PST)
Due to angle sum property of a triangle, we come to the conclusion that
∠APQ=∠SRQ
Consider ΔPTS and ΔRTA
TA=TS (Given)
∠RAT=∠PST(Given)
∠APQ=∠SRQ (Proved above)
Therefore, ΔPTS≅ΔRTA by AAS axiom of congruency.
Answer:
the graph on the right-top
Step-by-step explanation:
Transferring an "x" to the right side in
, we get 
The system of inequalities is

We have y=2x+2 - ascending function with a=2, b=2
b=2 shows that ascending function intersects Y-axis is in y=2 - that situation is only on the right-top and left-down. So, we refuse left-top and right-down.
y=-x-3 - descending function with a=-1, b=-3
y<2x+2 is an area below the ascending function and we see that on the left-
is an area above the descending function
On the left-down we have an area above both functions, so we refuse this picture
Right-top is correct
Answer:
10
3
Step-by-step explanation: