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Dafna1 [17]
2 years ago
14

14. There are 11 boys and 10 girls in a classroom. A teacher chooses a student at random and puts that student

Mathematics
2 answers:
lutik1710 [3]2 years ago
8 0

Answer:

here

Step-by-step explanation:

https://www.rcboe.org/cms/lib/GA01903614/Centricity/Domain/1351/21.2%20permutations%20and%20probability.pdf

exis [7]2 years ago
7 0

Yes because if she's going one in one out it is a chance thats what shes doing

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What is the quoteint of<br> 3/4 and 5/6
Novosadov [1.4K]

Answer:

9/10

Step-by-step explanation:

Very simple, Keep It, Change It, Flip it

Do 3/4 X 6/5 and you should get your answer

5 0
2 years ago
Find dy/dx if f(x) = (x + 8)^3x.
vlabodo [156]
This is quite a complex problem. I wrote out a really nice solution but I can't work out how to put it on the website as the app is very poorly made. Still, I'll just have to type it all in...

Okay so you need to use a technique called logarithmic differentiation. It seems quite unnatural to start with but the result is very impressive.

Let y = (x+8)^(3x)

Take the natural log of both sides:

ln(y) = ln((x+8)^(3x))

By laws of logarithms, this can be rearranged:

ln(y) = 3xln(x+8)

Next, differentiate both sides. By implicit differentiation:

d/dx(ln(y)) = 1/y dy/dx

The right hand side is harder to differentiate. Using the substitution u = 3x and v = ln(x+8):

d/dx(3xln(x+8)) = d/dx(uv)

du/dx = 3

Finding dv/dx is harder, and involves the chain rule. Let a = x+ 8:

v = ln(a)
da/dx = 1
dv/da = 1/a

By chain rule:

dv/dx = dv/da * da/dx = 1/a = 1/(x+8)

Finally, use the product rule:

d/dx(uv) = u * dv/dx + v * du/dx = 3x/(x+8) + 3ln(x+8)

This overall produces the equation:

1/y * dy/dx = 3x/(x+8) + 3ln(x+8)

We want to solve for dy/dx, achievable by multiplying both sides by y:

dy/dx = y(3x/(x+8) + 3ln(x+8))

Since we know y = (x+8)^(3x):

dy/dx = ((x+8)^(3x))(3x/(x+8) + 3ln(x+8))

Neatening this up a bit, we factorise out 3/(x+8):

dy/dx = (3(x+8)^(3x-1))(x + (x+8)ln(x+8))

Well wasn't that a marathon? It's a nightmare typing that in, I hope you can follow all the steps.

I hope this helped you :)
8 0
3 years ago
Help pls asap!!!!!!! brainliest!!!!!!
Andre45 [30]
The answer is C.
I did the work on a sticky note.
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3 years ago
Segment KJ shown below is the hypotenuse of isosceles right triangle JLK.
irga5000 [103]
On a coordinate plane it is negetive 5
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The answer would be D. In an inverse function, the x and y vlaues are switched (not in order though!).

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