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2 years ago

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A car travels 43 km in 56 minutes.

1 answer:

patriot [66]2 years ago

6 0

Answer:

$\displaystyle v=46.07\ Km/h$

Step-by-step explanation:

<u>Speed</u>

The speed is the ratio between the distance x traveled by an object and the time t taken.

$\displaystyle v=\frac{x}{t}$

The car travels x=43 Km in t=56 minutes. We are required to express the speed in Km/h. The time needs to be expressed in hours:

$t = 56 / 60 = 0.933\ h$

Now apply the formula:

$\boxed{\displaystyle v=\frac{43}{0.933}=46.07\ Km/h}$

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The triangle and the trapezoid have the same area. Base b2 is twice the length of base b1. What are the lenghts of the bases of

Sati [7]

Answer:

<h2>The lengths of the bases of the trapezoid:</h2><h2>42/h cm and 84/h cm.</h2>

Step-by-step explanation:

The formula of an area of a triangle:

$A=\dfrac{bh}{2}$

<em>b</em><em> </em>- base

<em>h</em> - height

We have <em>b = 21cm, h = 6cm</em>.

Substitute:

$A=\dfrac{(21)(6)}{2}=63\ cm^2$

The formula of an area of a trapezoid:

$A=\dfrac{b_1+b_2}{2}\cdot h$

<em>b₁, b₂</em> - bases

<em>h</em><em> - </em>height

We have <em>b₁ = 2b₂</em>, therefore <em>b₁ + b₂ = 2b₂ + b₂ = 3b₂</em>.

The area of a triangle and the area of a trapezoid are the same.

Therefore

$\dfrac{3b_2}{2}\cdot h=63$ <em>multiply both sides by 2</em>

$3b_2h=126$ <em>divide both sides by 3</em>

$b_2h=42$ <em>divide both sides by h</em>

$b_2=\dfrac{42}{h}$

$b_1=2b_2\to b_1=2\cdot\dfrac{42}{h}=\dfrac{84}{h}$

8 0

2 years ago

Read 2 more answers

Please help<br> Me with this

ratelena [41]

I belive that it would be 40% or .4

7 0

2 years ago

I need help with this

Harlamova29_29 [7]

Answer:

50 degrees.

Step-by-step explanation:

The three angles make up a straight line angle which = 180 degrees, so:

C = 180 - 65 - 65

= 50 degrees.

7 0

1 year ago

Read 2 more answers

Fill in the next entry in the pattern<br> 81, 27, 9, 3,

Dominik [7]

The answer to your problem is 1

6 0

3 years ago

Read 2 more answers

Consider a sample with data values of 27, 24, 21, 16, 30, 33, 28, and 24. Compute the 20th, 25th, 65th, and 75th percentiles. 20

densk [106]

Answer:

$P_{20} = 20$ --- 20th percentile

$P_{25} = 21.75$ --- 25th percentile

$P_{65} = 27.85$ --- 65th percentile

$P_{75} = 29.5$ --- 75th percentile

Step-by-step explanation:

Given

27, 24, 21, 16, 30, 33, 28, and 24.

N = 8

First, arrange the data in ascending order:

Arranged data: 16, 21, 24, 24, 27, 28, 30, 33

Solving (a): The 20th percentile

This is calculated as:

$P_{20} = 20 * \frac{N +1}{100}$

$P_{20} = 20 * \frac{8 +1}{100}$

$P_{20} = 20 * \frac{9}{100}$

$P_{20} = \frac{20 * 9}{100}$

$P_{20} = \frac{180}{100}$

$P_{20} = 1.8th\ item$

This is then calculated as:

$P_{20} = 1st\ Item +0.8(2nd\ Item - 1st\ Item)$

$P_{20} = 16 + 0.8*(21 - 16)$

$P_{20} = 16 + 0.8*5$

$P_{20} = 16 + 4$

$P_{20} = 20$

Solving (b): The 25th percentile

This is calculated as:

$P_{25} = 25 * \frac{N +1}{100}$

$P_{25} = 25 * \frac{8 +1}{100}$

$P_{25} = 25 * \frac{9}{100}$

$P_{25} = \frac{25 * 9}{100}$

$P_{25} = \frac{225}{100}$

$P_{25} = 2.25\ th$

This is then calculated as:

$P_{25} = 2nd\ item + 0.25(3rd\ item-2nd\ item)$

$P_{25} = 21 + 0.25(24-21)$

$P_{25} = 21 + 0.25(3)$

$P_{25} = 21 + 0.75$

$P_{25} = 21.75$

Solving (c): The 65th percentile

This is calculated as:

$P_{65} = 65 * \frac{N +1}{100}$

$P_{65} = 65 * \frac{8 +1}{100}$

$P_{65} = 65 * \frac{9}{100}$

$P_{65} = \frac{65 * 9}{100}$

$P_{65} = \frac{585}{100}$

$P_{65} = 5.85\th$

This is then calculated as:

$P_{65} = 5th + 0.85(6th - 5th)$

$P_{65} = 27 + 0.85(28 - 27)$

$P_{65} = 27 + 0.85(1)$

$P_{65} = 27 + 0.85$

$P_{65} = 27.85$

Solving (d): The 75th percentile

This is calculated as:

$P_{75} = 75 * \frac{N +1}{100}$

$P_{75} = 75 * \frac{8 +1}{100}$

$P_{75} = 75 * \frac{9}{100}$

$P_{75} = \frac{75 * 9}{100}$

$P_{75} = \frac{675}{100}$

$P_{75} = 6.75th$

This is then calculated as:

$P_{75} = 6th + 0.75(7th - 6th)$

$P_{75} = 28 + 0.75(30- 28)$

$P_{75} = 28 + 0.75(2)$

$P_{75} = 28 + 1.5$

$P_{75} = 29.5$

7 0

2 years ago