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Tanzania [10]
4 years ago
5

Ethanol will boil at 172.4 °F at standard

Physics
1 answer:
Fed [463]4 years ago
5 0

Answer:

78 degree C

Explanation:

(F-32)*5/9

(172.4-32)*5/9=78

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Air in human lungs has a temperature of 37.0°C and a saturation vapor density of 44.0 g/m³.
ioda

Answer:

(a). The maximum loss of water vapor by the person is 8.8\times10^{-2}\ g

(b). The partial pressure of water vapor is 6.29\times10^{3}\ N/m^2

Explanation:

Given that,

Temperature = 37.0°C

Volume of air = 2.00 L

Density of vapor = 44.0 g/m³

We need to calculate the maximum loss of water vapor by the person

Using formula of density

m=\rho_{air}\times V_{air}

Put the value into the formula

m=44.0\times2.00\times10^{-3}

m=0.088\ g

m=8.8\times10^{-2}\ g

(b). We need to calculate the partial pressure of water vapor

Using formula of pressure

PV=nRT

P=\dfrac{nRT}{V}

P=\dfrac{\rho\times R\times T}{M}

Put the value into the formula

P=\dfrac{44\times8.314\times(37+273)}{18.01528}

P=6294.82\ N/m^2

P=6.29\times10^{3}\ N/m^2

Hence, (a). The maximum loss of water vapor by the person is 8.8\times10^{-2}\ g

(b). The partial pressure of water vapor is 6.29\times10^{3}\ N/m^2

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4 years ago
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photoshop1234 [79]
750 divide 50 which is 15n

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