There are various reasons why a measurement tool cannot be accurate. One of them is thermal contraction and expansion varies according to seasons.
<h3>What are Accuracy and Precision?</h3>
There are two ways to assess observational error: accuracy and precision. Precision measures how closely two measurements are to one another, whereas accuracy measures how close a group of measurements is to its actual value. In other words, precision is a measure of statistical variability and a description of random errors.
We can say that a tool can be precise, but it cannot be accurate. There are various reasons behind that, some of them are :
- It may not be calibrated properly. If there are no reliable standards to use for calibration, this may occur.
- Perhaps it strayed. This is why electronic scales include a tare function—they are terrible in this area.
- Perhaps the measurements are not linear. Our calipers might have been quite precise at the 2-inch standard, where they were calibrated, but inaccurate at other dimensions.
- Temperature is one environmental component that the instrument might be sensitive to. These effects might be compensated for, but the compensation might not be ideal. This issue affects both dissolved solids meters and picometers.
These are some of the reasons due to which measurement tool cannot be accurate.
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Answer:
One may assume that the planet radiates energy like a blackbody at some temperature according to the Stefan–Boltzmann law. Thermal equilibrium exists when the power supplied by the star is equal to the power emitted by the planet. The temperature at which this balance occurs is the planetary equilibrium temperature.
Explanation:
I think answer should be d. Please give me brainlest I hope this helps let me know if it’s correct or not okay thanks I appreciate it
1.) What type of energy is associated with motion? Kinetic energy
2)List 3 items that store chemical energy ?
Coal
Apple
Chemical batteries
For this problem, we use the equations derived for rectilinear motion at constant acceleration. The equations are:
a = (v - v₀)/t
x = v₀t + 0.5at²
where
a is acceleration
v and v₀ are the final and initial velocities, respectively
x is the distance
t is the time
First, let's determine the a to be used in the second equation:
a = (7.5 m/s - 0 m/s)/1.7 s = 4.411 m/s²
x = (0)(1.7s) + 0.5(4.411 m/s²)(1.7 s)²
x = 6.375 m