A beam of electrons with of wavelength of 7.5 x 10-6 m is incident on a pair of narrow rectangular slits separated by 0.75 mm. T
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Answer:
frequency = 104.80 Hz
wavelength = 0.567 m
frequency = 104.80 Hz
wavelength = 3.27 m
Explanation:
given data
mass m = 9.4 g = 9.4 × m
length L = 85 cm = 0.85 m
tension T = 39 N
to find out
frequency and wavelength
solution
first we find frequency for second overtone
f = 3 /2L × √(T/μ) .............1
put here all value and
here μ = m/L = 9.4 × / 0.85 = 1.10588 ×
kg/m
f = 3 /2(0.85) × √(39/1.10588 ×)
f = 104.80 Hz
and
wavelength is 2L/3
wavelength = 2(0.85) / 3
wavelength = 0.567 m
and
frequency = 104.80 Hz
and
wavelength by speed of sound i.e 343 m/s
wavelength = speed / f
wavelength = 343 / 104.80
wavelength = 3.27 m