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Lelechka [254]
3 years ago
13

When placed at a certain point, a

Physics
1 answer:
Wewaii [24]3 years ago
6 0

Answer: 180

Explanation: Acellus

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The light emitted by an argon laser light includes light with a wavelength of 488 nm. what is the frequency of this light? 6.15
Paraphin [41]
Frequency and wavelength are inversely related. That is, when frequency increases, the value of the wavelength decreases and vice versa. The constant of proportionality of  the relation is the speed of light that has a value of 3.0x10^8 m/s. We calculate as follows:

wavelength = speed of light /frequency
488x10^-9 = 3.8x10^8 / frequency
frequency = 6.15x10^14 /s = 6.15x10^14 Hz ------> OPTION 3
3 0
4 years ago
Calculate the number of millimeters in 2.13 kilometer.
lapo4ka [179]

The answer is 2,130,000

6 0
4 years ago
An archer fish spies a meal of a grasshopper sitting on a long stalk of grass at the edge of the pond in which he is swimming. I
andrew-mc [135]

Answer:

The archerfish must spit at a minimum speed of 3.43m/s at an angle of 69.14\° above the horizontal.

Explanation:

Hi

First of all, we need to find the angle above the horizontal at which the archerfish must spit, as we can see in the attachment this angle is \Theta = 69.14\°.

Then we use the formula h=\frac{v_{0}^{2}sin^{2} \Theta}{2g}, as we clear it for v_{0}, we obtain, v_{0}=\frac{\sqrt{2gh} }{sin\Theta}=\frac{\sqrt{2(9.8m/s^{2})(0.525m)} }{sin(69.14\°)}=3.43m/s, therefore the archerfish must spit at a minimum speed of 3.43m/s at an angle of 69.14\° above the horizontal.

7 0
3 years ago
A very long thin wire carries a uniformly distributed charge, which creates an electric field. The electric field is (2300 N/C ,
Leto [7]

Answer:

λ= 5.24 × 10 ⁻² nC/cm

Explanation:

Given:

distance r = 4.10 cm = 0.041 m

Electric field intensity E = 2300 N/C

K = 9 x 10 ⁹ Nm²/C

To find λ = linear charge density = ?

Sol:

we know that E= 2Kλ / r

⇒ λ = -E r/2K         (-ve sign show the direction toward the wire)

λ = (- 2300 N/C × 0.041 m) / 2 ×  9 x 10 ⁹ Nm²/C

λ = 5.24 × 10 ⁻⁹ C/m

λ = 5.24 nC/m = 5.24 nC/100 cm

λ= 5.24 × 10 ⁻² nC/cm

3 0
3 years ago
Hi please answer and show your work​
jek_recluse [69]

Answer:

\huge\boxed{\sf P.E. = 240\ MJ}

\huge\boxed{\sf K.E. = 19.6\ MJ}

Explanation:

<u>Given:</u>

Mass = m = 200,000 kg

Vertical Distance = h = 120 m

Speed = v = 14 m/s

Acceleration due to gravity = g = 10 m/s²

<u>Required:</u>

1) Gravitational Potential Energy = P.E = ?

2) Kinetic Energy = K.E. = ?

<u>Formula:</u>

1) P.E. = mgh

2) K.E. = \displaystyle \frac{1}{2} mv^2

<u>Solution:</u>

1) P.E. = (200,000)(10)(120)

P.E. = 240,000,000 Joules

P.E. = 240 Mega Joules

P.E. = 240 MJ

2) K.E. = 1/2 (200000)(14)^2

K.E. = (100000)(196)

K.E. = 19,600,000 Joules

K.E. = 19.6 MJ

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
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