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Naddika [18.5K]
3 years ago
13

Two men, 400 feet apart, observe a balloon between them; it is in the same vertical plane as they are. The respective angles of

elevation of the balloon are observed by the men to be 75°20' and 49°30'. Find x rounded to the nearest whole number.

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
7 0

Answer:

471 ft.

Step-by-step explanation:

Stels [109]3 years ago
6 0
Because x is not defined, it is assumed to be the height of the balloon.

Note that
75° 20' = 75.333°
49° 30' = 49.5°

From the figure shown below, obtain by definition,
a = x cot 49.5° = 0.8541x
b = x cot 75.333° = 0.2617x

Because a + b = 400 ft, therefore
0.8541x + 0.2617x = 400
1.1158x = 400
x = 358.49 ft

Answer: 358 ft (nearest whole number)

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In a survey, the planning value for the population proportion is p* = 0.35. How large a sample should be taken to provide a 95%
lions [1.4K]

Answer:

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59  

And rounded up we have that n=350  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest

\aht p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)

And replacing into equation (b) the values from part a we got:  

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59  

And rounded up we have that n=350  

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tekilochka [14]
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