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3 years ago

14

PLEASE HELP!! Tell me the IUPAC name of the following compounds:

1 answer:

leonid [27]3 years ago

4 0

The IUPAC rules are

a) Find out the longest chain of carbon in the given organic compound

b) We will name the longest chain.

c) We will identify the main functional group and will assign a suffix to the compound.

d) We will number the carbons in the longest chain selected so that the attached groups attain lowest numeral as substituent

e) We will name the side groups or chains.

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Aluminum chloride can be formed from its elements:

saul85 [17]

<u>Answer:</u> The $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical reaction for the formation reaction of $AlCl_3$ is:

$2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3 (s)$ $\Delta H^o_{formation}=?$

The intermediate balanced chemical reaction are:

(1) $HCl(g)\rightarrow HCl(aq.)$ $\Delta H_1=-74.8kJ$ ( × 6)

(2) $H_2(g)+Cl_2(g)\rightarrow 2HCl(g)$ $\Delta H_2=-185kJ$ ( × 3)

(3) $AlCl_3(aq.)\rightarrow AlCl_3(s)$ $\Delta H_3=+323kJ$ ( × 2)

(4) $2Al(s)+6HCl(aq.)\rightarrow 2AlCl_3(aq.)+3H_2(g)$ $\Delta H_4=-1049kJ$

The expression for enthalpy of formation of $AlCl_3$ is,

$\Delta H^o_{formation}=[6\times \Delta H_1]+[3\times \Delta H_2]+[2\times \Delta H_3]+[1\times \Delta H_4]$

Putting values in above equation, we get:

$\Delta H^o_{formation}=[(-74.8\times 6)+(-185\times 3)+(323\times 2)+(-1049\times 1)]=-1406.8kJ$

Hence, the $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

6 0

3 years ago

6.626 × 10⁻³⁴ × 7.08× 10¹⁴

PolarNik [594]

The answer is 4.69 x 10⁻¹⁹ I hope this helped!

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3 years ago

Which family contains elements with a full octet of valence electrons?

iren [92.7K]

D. the noble gasses !!!!

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3 years ago

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What is the third alkali metal

andrey2020 [161]

Answer:

potassium

The third alkali metal is K (potassium). The atomic number of K (potassium) is 19. Thus, the atomic number of third alkali metal is 19

Explanation:

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3 years ago

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The concentration of sugar in Coke is approximately 10%, or 100 ppt. If you drink

masya89 [10]

Answer:

35.5g of sugar

Explanation:

To solve this question we must assume the density of coke = Density of water = 1g/mL

Thus, in a single can of coke, the mass is 355g. Now, the 10% of this coke is sugar. That means the amount of sugar you are consuming is:

355g * (10/100) = 35.5g of sugar

<em>10/100 = 10%</em>

7 0

3 years ago