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viktelen [127]
3 years ago
6

Sodium hydroxide +ammonium sulphate ==>ammonia+sodium sulphate+water coefficients ​

Chemistry
1 answer:
zysi [14]3 years ago
8 0

Answer:

Below

Explanation:

Balanced equation: 2NaOH + (NH4)2SO4 = 2NH3 + 2H2O + Na2SO4

The coefficients would be 2

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What evidence do you have that tpgs-750m increases the reaction rate? How does tpgs-750m act to increase the reaction rate?
notka56 [123]

TPGS-750 M conducts reaction under lower temperature then the reactions carried out in organic solvents.

<h3>What is tpgs-750m ?</h3>

It is a chemical molecule of the second generation known as an amphiphile, with both hydrophilic and lipophilic qualities.

  • In contrast to any other organic solvent, water is used for transition metal catalysed cross-coupling, making TPGS-750M a second generation surfactant with physical features that encourage this process.

  • The hydrophilic portion of TPGS-750M, which is utilised in medicine, is made of Poly(ethylene glycol), and the hydrophobic portion is made of the vitamin E compound alpha-tocopherol.

Learn more about Reaction rate here:

brainly.com/question/25724512

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7 0
1 year ago
Which gas has approximately the same density as c2h6 at stp no nh3 h20 so2?
zmey [24]
1 mole of any gas occupy 22.4 L at STP (standard temperature and pressure, 0°C and 1 atm).

Let given gases be 1 mole. So their volumes will be the same, 22.4 liters.

Density is the ratio of mass to volume.

By formula; density= mass/volume; d=m/V

To find out masses of gases, do the mole calculation.

By formula; mole= mass/molar mass; n= m/M; m= n*M

Molar masses are calculated as
1. C₂H₆ (ethane)                 = 2*12 g/mol + 6*1 g/mol= 30 g/mol
2. NO (nitrogen monoxide) = 1*14 g/mol + 1*16 g/mol= 30 g/mol
3. NH₃ (ammonia)              = 1*14 g/mol + 3*1 g/mol= 17 g/mol
4. H₂O (water)                    = 2*1 g/mol + 1*16 g/mol= 18 g/mol
5. SO₂ (sulfur dioxide)        = 1*32 g/mol + 2*16 g/mol= 64 g/mol
Use Periodic Table to get atomic mass of elements.

Since their volumes are equal, compounds having the same molar mass will have the same density. 
Recall the formula d= m/V.

Ethane and nitrogen monoxide have the same density.

The answer is C₂H₆ and NO.
6 0
3 years ago
Why will a solid dissolve in one substance but not another?
Molodets [167]

<u><em>Answer: Water also dissolves non-ionic substances. ... Many substances do not dissolve in water and that is because they are non-polar and do not interact well with water molecules. A common example is oil and water. Oil contains molecules that are non-polar, thus they do not dissolve in water.</em></u>

Explanation:

8 0
3 years ago
235
lisov135 [29]

Answer:

Average atomic mass of uranium = 237.97 amu

Explanation:

Given data:

Abundance of U-234 = 0.01%

Abundance of U-235 = 0.71%

Abundance of U-238 = 99.28%

Average atomic mass of uranium = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass)  / 100

Average atomic mass  = (234×0.01)+(235×0.71)+(238+99.28) /100

Average atomic mass =  2.34 + 166.85+23628.64 / 100

Average atomic mass = 23797.83 / 100

Average atomic mass = 237.97 amu.

3 0
3 years ago
is the general formula of a certain hydrate. When 256.3 g of the compound is heated to drive off the water, 214.2 g of anhydrous
Marizza181 [45]

Answer:

The general formula of the hydrate is Caa Seb Oc. nH2O. Based on the given information, the weight of the hydrated compound is 256.3 grams, the weight of the anhydrous compound is 214.2 grams.  

Therefore, the weight of water evaporated is 256.3 g - 214.2 g = 42.1 grams

The molecular weight of water is 18 gram per mole. So, the number of moles of water will be,  

Moles of water = weight of water/molecular weight

= 42.1 grams / 18 = 2.3

The given composition of calcium is 21.90 %. So, the concentration of calcium in anhydrous compound is,  

= 214.2 * 0.2190 = 46.91 grams

The given composition of Se is 43.14 %. So, the concentration of selenium in anhydrous compound is,

= 214.2 * 0.4314 = 92.40 grams

The given composition of oxygen is 34.97%, So, the concentration of oxygen in anhydrous compound is,  

= 214.2 * 0.3497 = 74.91 grams

The molecular weight of Ca is 40.078, the obtained concentration is 46.91 grams, stoichiometry will be, 46.91/40.078 = 1.17

The molecular weight of Se is 78.96, the obtained concentration is 92.40, stoichiometry will be,  

92.40/78.96 = 1.17

The molecular weight of Oxygen is 15.999, the concentration obtained is 74.91, the stoichiometry will be,  

74.91/15.999 = 4.68.  

Thus, the formula becomes, Ca1.17. Se1.1e O4.68. 2.3H2O, the closest actual component is CaSeO4.2H2O

6 0
4 years ago
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