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2 years ago

Explain the difference between a solar and a lunar eclipse.

Chemistry

1 answer:

Zinaida [17]2 years ago

7 0

Answer:

A lunar eclipse occurs at night and a solar eclipse occurs during the day. There are only certain times when either of them can occur. A lunar eclipse can only occur when the moon is directly opposite the Sun in the sky — a full moon. Even though there is a full moon each month, obviously a lunar eclipse does not occur on a monthly basis because the Sun isn't exactly in line with the Earth and the moon. The moon's orbit is actually tilted 5 degrees more than that of the Earth; otherwise, we would see a lunar eclipse each month.

Explanation:

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3 years ago

Part 1: Use complete sentences to explain why solar storms occur.

Virty [35]

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3 years ago

What are the characteristics of the actinides?

iren [92.7K]

The Actinide series contains elements with atomic #'s 89 to 103 and is the sixth group in the periodic table. This series is below the Lanthanide series, which is located under the main body of the periodic table. Both Actinide and Lanthanide series are refered to as Rare Earth Metals. Hope this helped

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3 years ago

Calculate the liters of a 4.40 M KCl solution to obtain 0.200 mole of KCI

Yuki888 [10]

Answer:

$\boxed {\boxed {\sf 0.0455 \ L}}$

Explanation:

We are asked to calculate the liters given the molarity and moles in a solution.

Molarity is a measure of concentration in moles per liter. It is calculated with the following solution:

$molarity= \frac{moles \ of \ solute}{liters \ of \ solution}$

The molarity of the solution is 4.40 molar of potassium chloride (KCl). 1 molar is equal to 1 mole per liter, so the molarity is also 4.40 moles of potassium chloride per liter. There are 0.200 moles of potassium chloride or solute. The liters of solution is unknown, so we can use the variable x.

molarity= 4.40 moles KCl / L
moles of solute = 0.200 mol KCl
liters of solution = x

$4.40 \ mol \ KCl/ L = \frac{ 0.200 \ mol \ KCl}{x}$

Since we are solving for x, we must isolate the variable. First, cross multiply. Multiply the first numerator by the second denominator, then the first denominator and the second numerator.

$\frac {4.40 \ mol \ KCl/ L}{1} = \frac{ 0.200 \ mol \ KCl}{x}$

$4.40 \ mol \ KCl / L * x= 1 * 0.200 \ mol \ KCl$

$4.40 \ mol \ KCl / L * x= 0.200 \ mol \ KCl$

x is being multiplied by 4.40 moles of potassium chloride per liter. The inverse operation of multiplication is division. Divide both sides by 4.40 mol KCl/L

$\frac {4.40 \ mol \ KCl / L * x}{4.40 \ mol \ KCl / L}= \frac {0.200 \ mol \ KCl}{{4.40 \ mol \ KCl / L}}$

$x= \frac {0.200 \ mol \ KCl}{{4.40 \ mol \ KCl / L}}$

The units of moles of potassium chloride cancel.

$x= \frac {0.200}{{4.40 L}}$

$x= 0.0454545454545 \ L$

The original measurements of liters and moles have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ten-thousandth place (0.0454545454545). The 5 to the right of this place (0.0454545454545) tells us to round the 4 up to a 5.

$x \approx 0.455 \ L$