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zzz [600]
2 years ago
10

What is an equation of the line that passes through the point(-1,-3) and is perpendicularly to the line x-2y=14

Mathematics
2 answers:
Nitella [24]2 years ago
8 0

Answer:

the equation will be

Step-by-step explanation:

2x+y+5=0

IRINA_888 [86]2 years ago
6 0

Answer:

2x + y + 5 = 0

Step-by-step explanation:

The equation of line is x-2y = 14 and we need to find the equⁿ of line which passes through (-1,-3) and is perpendicular to given line.

  • Find the slope of given line by converting it into slope intercept form.

=> x - 2y = 14

=> 2y = x - 14

=> y = x-14/2

=> y = x/2 - 7

  • Comparing to y = mx + c ,

=> Slope (m) = 1/2 .

Now the slope of line perpendicular to it , will have a slope ,

=>m_{perp} = -1/m

=>m_{perp} = -1/½

=> m_{perp} = -2

  • Using point slope form ,

=> m = (y - y₁) / ( x - x₁)

=> -2 = { y - (-3) } / { x - (-1) }

=> -2 = y + 3/x + 1

=> -2(x + 1) = y + 3

=> -2x -2 = y + 3

=> y + 2x +3+2 = 0

=> 2x + y + 5 = 0

<h3><u>Hence </u><u>the</u><u> </u><u>equation</u><u> of</u><u> </u><u>line </u><u>perpendicular</u><u> to</u><u> it</u><u> </u><u>is </u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>y </u><u>+</u><u> </u><u>5</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>.</u></h3>

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