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3 years ago

Can someone plz help with this asap

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

6 0

Answer:

Horizontal lines are parallel to the x-axis

The answer is the second option

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A circle is centered on Point B. Points A, C, and D lie on it’s circumference. If Angle ADC measures 61 Degrees, what does Angle

Nostrana [21]

Answer:

122

Step-by-step explanation:

61 x 2 = 122

6 0

3 years ago

Read 2 more answers

URGENT HELPPP !!!!!! Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!

GaryK [48]

Answer:

(8,-3)

Step-by-step explanation:

I just added 1 to the x value and added 2 to the y value because that was the difference between point A and the midpoint of the segment.

Hope this helps!

3 0

2 years ago

Please help me am I. troubles

Zanzabum

Answer:

$\frac{ {x}^{2} }{y(x - y)} + \frac{ {y}^{2} }{ - x(x - y)}$

$\frac{ {x}^{2} }{y(x - y)} - \frac{ {y}^{2} }{x(x - y)}$

$\frac{ {x}^{2} \times x - {y}^{2} \times y}{xy(x -y)}$

$\frac{(x - y)( {x}^{2} + xy + {y}^{2}) }{xy(x - y)}$

$\frac{ {x}^{2} + xy + {y}^{2} }{xy}$

7 0

2 years ago

The mean annual income for people in a certain city is 37 thousand dollars, with a standard deviation of 28 thousand dollars. A

Aloiza [94]

Answer:

$P( 31 < \bar X< 41)$

And we can ue the z score formula given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got for the limits:

$z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515$

$z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01$

So we want to find this probability:

$P(-1.515$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the annual income of a population, and for this case we know the following info:

$\mu=37$ and $\sigma=28$ and we are omitting the zeros from the thousand to simplify calculations

We select a sample size of n=50>30.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by: