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VladimirAG [237]
3 years ago
10

Find an equation for the nth term of the arithmetic sequence.

Mathematics
1 answer:
babymother [125]3 years ago
7 0

Answer:

The common difference would be calculated as:

(a21-a19)/2

(-164--(-58 ))/2 (Replacing the values )

(-164 +58)/2 (Changing signs)

(-106)/2(Subtracting)

-53

Then we are going to replace the common difference(d) in the sequence formal with the 21st term . It is done for finding the first term of the sequence.

a21=a0+d*(n-1)

-164=a0+-53*(21-1) (Replacing the values)

-164=a1-53(20) (Subtracting)

-164=a1-1060 (Multiplying )

-164+1060=a1 (Adding 1060 on both sides of the equation)

896=a1

The answer would be : an= 896-53*(n-1), which is the option B.

PLEASE MARK ME AS BRAINLIEST

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Using the following diagram, solve for X.
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Answer:

17.5

Step-by-step explanation:

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I need help showing work and explain the reason
dimulka [17.4K]

Answer:

Ok

Step-by-step explanation:

-3x-5=16

at 5 to both sides

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divide by -3

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8 0
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Henry’s disability insurance pays 70% of his salary for up to 26 weeks if his salary is $450 and he is disabled for 20 weeks how
ankoles [38]

Answer:

$1575

Step-by-step explanation:

70 % of his salary is 0.7 X 450 = 315

He gets it for 20 weeks

presuming the salary is monthly.

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6 0
4 years ago
A cylinder has a volume of 216 pi cubic feet and a hi of 18 ft what is the area of the base? Cylinder v equals BH
VARVARA [1.3K]

Answer:

12π ft² or 37.7 ft²

Step-by-step explanation:

The volume of a cylinder is given by the area of its base multiplied by its height. If total volume is 216 π ft³ and the height is 18 ft, then the area of the base is:

V = Bh\\216\pi = B*18\\B= 12\pi \ ft^2

The base has an area of 12π ft² or 37.7 ft².

7 0
3 years ago
How do I graph the linear equation y=-1/2x + 4
shtirl [24]

Answer:

The Two points for the line  y =\frac{-1}{2}x+4 are

point A( x₁ , y₁) ≡ ( 0 , 4)

point B( x₂ , y₂) ≡ (8 , 0)  

The Graph is attached below.

Step-by-step explanation:

Given:

y =\frac{-1}{2}x+4........... equation of a line  Given

Let the points be point A, and point B  

To Find:

point A( x₁ , y₁) ≡  ?

point B( x₂ , y₂) ≡ ?

Solution:

For Drawing a graph we require minimum two points but we will have here.

For point A( x₁ , y₁)

Put x = 0 in the given equation we get

y =\frac{-1}{2}0+4\\\\y=4

∴ point A( x₁ , y₁) ≡ ( 0 , 4)

For point B( x₂ , y₂)

Put y= 0 in the given equation we get

0 =\frac{-1}{2}x+4\\\\x=8

∴ point B( x₂ , y₂)  ≡ (8 , 0)

Therefore,

The  points for the line  y =\frac{-1}{2}x+4 are

point A( x₁ , y₁) ≡ ( 0 , 4) (blue color point on the graph)

point B( x₂ , y₂) ≡ (8 , 0) (green color point on the graph)

The Graph is attached below..

5 0
3 years ago
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