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3 years ago

WILL GIVE BRAINLIST

Mathematics

2 answers:

Rom4ik [11]3 years ago

5 0

Answer:

7:8 7:8

Step-by-step explanation:

if you subtract 28 from 42 and subtract 32 from 48 then you get 14-16. then double it and you get 28-32 then add 14-16 to those again and you get 42-48. because they add up and are equal, take 14-16 and simplify it to 7:8.

Sergio [31]3 years ago

3 0

= Ratio of minutes to miles in which Samuel drove = 28 : 32

= Ratio of minutes to miles in which Beverly drove = 42 : 48

To find whether the time they drove and the distance they covered were proportional or not , let us first change them into a fraction and then simplify them .

= 28 : 32 = 28/32

= 28/32

Both the numerator and the denominator is divisible by 4 .

= 28 ÷ 4 / 32 ÷ 4

= 7/8 = 7 : 8

Samuel = 7 : 8

Beverly = 42 : 48 = 42/48

= 42/48

Both the numerator and the denominator is divisible by 6 .

= 42 ÷ 6 / 48 ÷ 6

= 7/8

Therefore, the ratio of miles to minutes drove by Samuel and Beverly is proportional , 7:8 :: 7:8

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Express the decimal 0.43 as a fraction in its simplest form.

maks197457 [2]

Answer:

Step-by-step explanation:

43/100 or 43%

3 0

3 years ago

With your typical convenience store customer, there is a 0.23 probability of buying gasoline. The probability of buying grocerie

Trava [24]

Answer:

a) P ( A & B ) = 0.1995

b) P (A U B ) = 0.7905

c) P (A/B) = 0.2625

d) P(B/A') = 0.194805

e) NOT mutually exclusive

f) NOT Independent

Step-by-step explanation:

Declare Events:

- buying gasoline = Event A

- buying groceries = Event B

Given:

- P(A) = 0.23

- P(B) = 0.76

- P(B/A) = 0.85

Find:

- a. Find the probability that a typical customer buys both gasoline and groceries.

- b. Find the probability that a typical customer buys gasoline or groceries.

- c. Find the conditional probability of buying gasoline given that the customer buys groceries.

- d. Find the conditional probability of buying groceries given that the customer did not buy gasoline.

- e Are these two events (groceries, gasoline) mutually exclusive?

- f Are these two events independent?

Solution:

- a) P ( A & B ) ?

P ( A & B ) = P(B/A) * P(A) = 0.85*0.23 = 0.1995

- b) P (A U B ) ?

P (A U B ) = P(A) + P(B) - P(A&B)

P (A U B ) = 0.23 + 0.76 - 0.1995

P (A U B ) = 0.7905

- c) P ( A / B )?

P ( A / B ) = P(A&B) / P(B)

= 0.1995 / 0.76

= 0.2625

- d) P( B / A') ?

P( B / A') = P ( B & A') / P(A')

P ( B & A' ) = 1 - P( A / B) = 1 - 0.85 = 0.15

P ( B / A' ) = 0.15 / (1 - 0.23)

= 0.194805

- e) Are the mutually exclusive ?

The condition for mutually exclusive events is as follows:

P ( A & B ) = 0 for mutually exclusive events.

In our case P ( A & B ) = 0.1995 is not zero.

Hence, NOT MUTUALLY EXCLUSIVE

- f) Are the two events independent?

The condition for independent events is as follows:

P ( A & B ) = P (A) * P(B) for mutually exclusive events.

In our case,

0.1995 = 0.23*0.76

0.1995 = 0.1748 (NOT EQUAL)

Hence, NOT INDEPENDENT

6 0

3 years ago

What is the equation to this table?use y=mx+b

nirvana33 [79]

Answer:

y=2x+4

Step-by-step explanation:

4 0

2 years ago

6th grade math guys! (:

andrew-mc [135]

Answer:

Option D, 6(x + 4)

Step-by-step explanation:

<u>Step 1: Combine Like Terms</u>

3x + 14 + 3x + 10

6x + 24

6x + 24

6(x + 4)

Answer: Option D, 6(x + 4)

6 0

2 years ago

Read 2 more answers

While organizing her DVD collection, Jessica put 5 DVDs on the first rack, 10 DVDs on the second rack, 20 DVDs on the third rack

aleksandrvk [35]

Answer:

160

Step-by-step explanation:

Number of DVDs put on the first rack = 5

Number of DVDs put on the second rack = 10

If we closely observe, the number of DVDs on the second rack is nothing but number of DVDs on the first rack multiplied by 2.

Number of DVDs put on the third rack = 20

If we closely observe, the number of DVDs on the third rack is nothing but number of DVDs on the second rack multiplied by 2.

Number of DVDs put on the fourth rack = 40

If we closely observe, the number of DVDs on the fourth rack is nothing but number of DVDs on the third rack multiplied by 2.

Number of DVDs put on the fifth rack = 80

If we closely observe, the number of DVDs on the fifth rack is nothing but number of DVDs on the fourth rack multiplied by 2.

Therefore, to find the number of DVDs on the sixth rack as per similar pattern, we need to multiply the number of DVDs on the fifth rack with 2.

Number of DVDs on the sixth rack = $80\times 2 = \bold{160}$

4 0

3 years ago