All categories

3 years ago

Which of the following geometric solids has five faces and five vertices?

Mathematics

1 answer:

nikitadnepr [17]3 years ago

3 0

A square pyramid has five faces and five vertices.

You might be interested in

Please help I need answers. zoom in if you can't see it

Evgesh-ka [11]

Answer:

The answer is a, 8+s=10

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

HELP WITH THIS MATH PROBLEM 93. Points

nadya68 [22]

Answers:

4; 20; 3x² - 4x + 3; 52; 17

Step-by-step explanation:

f(-1): replace x in f(x) = x² + 3 with -1: f(-1) = (-1)² + 3 = 4

f(-4) + g(-1) = (-4)² + 3 + 2(-1) + 3 = 16 + 3 - 2 + 3 = 20 (since g(x) = 2X + 3)

3f(x) - 2g(x) = 3[x² +3] - 2[2x + 3} = 3x² + 9 - 4x - 6 = 3x² - 4x + 3

f(g(2)): First, evaluate g(2). It is g(2) = 2(2) + 3 = 7. Next, use this output, 7, as the input to f(x): f(g(x)) = (7)² + 3 = 49 + 3 = 52

g(f(2)): First, evaluate f(x) at x = 2: f(2) = (2)² + 3 = 7. Next, use this 7 as the input to g(x): g(f(2)) = g(7) = 2(7) + 3 = 17

8 0

4 years ago

Read 2 more answers

15 points! The data set shows the weights of pumpkins, in pounds, that are chosen for a photograph in a farming magazine. The re

vladimir2022 [97]

Answer:

Step-by-step explanation:

a). Mean of the given data set = $\frac{32+28+18+40+22}{5}$

= 28

b). x $x-\overline{x}$ $(x-\overline{x})^2$

32 32-28 = 4 16

28 28 - 28 = 0 0

18 18 - 28 = -10 100

40 40 - 28 = 12 144

22 22 - 28 = -6 36

$\sum({x-\overline x})^2$ = 296

c). Standard deviation = $\sqrt{\frac{\sum (x-\overline{x})^2}{n}}$

= $\sqrt{\frac{296}{5} }$

= 7.69

d). Mean of the new set of weights = $\frac{32+33+34+35+36}{5}$

= 34

Since mean of the data set is more close to each data, standard deviation will be less than the deviation given in part (c).

7 0

3 years ago

A person earns $32,600 one year and receives a 5% raise in salary. What is the new salary?

notka56 [123]

(32600/100) x 5 = 1630
32600+1630= 34230$

3 0

3 years ago

A boat is pulled toward a dock by means of a rope wound on a drum that is located 6 ft above the bow of the boat. If the rope is

Monica [59]

Answer:

Step-by-step explanation:

Given that:

The height of the dock (h) = 6

Let represent d to be the distance between the boat and the dock

Let the length of the rope between the boat and the drum be denoted by (l)

Then, the rate of change for the length of the rope be:

dl/dt = -5 ft/s

Using Pythagoras rule to determine the relationship between these values, we have:

$l^2 = h^2 +d^2$

$l^2 = 6^2 + d^2$

$l^2 = 36 + d^2$

We relate to: $2l * \dfrac{dl}{dt} = 2d* \dfrac{dd}{dt}$

From the question;

l = 34,

So to find $\dfrac{dd}{dt}$ , we get;

$d = \sqrt{l^2 - 36}$

$d = \sqrt{34^2 - 36}$

$d = \sqrt{1156- 36}$

$d = \sqrt{1120}$

d = 33.46

So, we have:

$\dfrac{dd}{dt}= \dfrac{l}{d} \times \dfrac{dl}{dt}$

$\dfrac{dd}{dt}= \dfrac{34}{33.46} \times - 5$

$\dfrac{dd}{dt}= 1.016 \times - 5$

$\dfrac{dd}{dt}=-5.08 \ ft/sec$

4 0

3 years ago