The blue line...
(1,2),(3,1)
slope = (1 - 2) / (3 - 1) = -1/2
there is a y int at (0,2.5) or (0,5/2)
it is shaded below the line....and it is a solid line
this inequality is :
y = -1/2x + 5/2
1/2x + y = 5/2
x + 2y = 5
x + 2y < = 5.....this is ur inequality
red line...
(0,4), (1,1)
slope = (1 - 4) / (1 - 0) = -3/1 = -3
there is a y int at (0,4)
it is shaded below the line...and it is a solid line
this inequality is :
y = -3x + 4
3x + y = 4
3x + y < = 4 ...this is ur inequality
summary :
ur 2 inequalities are :
x + 2y < = 5 and 3x + y < = 4
Answer:
9/11 = 27/33
2/3 = 22/33
27/33 + 22/33 = 49/33
Step-by-step explanation:
Answer:
(-6,0)
Step-by-step explanation:
the y-axis is any (x number, 0)
9514 1404 393
Answer:
- red division: 6 teams
- blue division: 5 teams
Step-by-step explanation:
We can let r and b represent the numbers of teams in the red and blue divisions, respectively. The total number of goals scored in each division will be the average for that division times the number of teams in that division.
r - b = 1 . . . . . . there is 1 more red team than blue
4.5r +4.2b = 48 . . . . . . total goals scored per week
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Solving by substitution, we have ...
r = b +1
4.5(b +1) +4.2b = 48 . . . . substitute for r
8.7b +4.5 = 48 . . . . . . . . simplify
8.7b = 43.5 . . . . . . . . . . subtract 4.5
b = 43.5/8.7 = 5 . . . . . divide by 8.7
r = b +1 = 6 . . . . . . . . . find r
There are 6 red teams and 5 blue teams.
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<em>Additional comment</em>
The basic idea is that you make an equation for each relation given in the problem statement. For a problem like this, you do need to have an understanding of how the average number of goals would be calculated and how that relates to the total goals.