Answer:
The average angle at which the airplane must descend for landing is 21°
Step-by-step explanation:
Here, we have question related to angle of elevation and depression
The height of the airplane be, y = 10,000 ft
The Location of the airport is, x = 50 miles = 26400 ft
Therefore,
we have,
Let the average angle be θ
Therefore,

The opposite to the angle of descent is the height and the adjacent is the distance of the airport away from the airplane
Therefore, tan θ = 
Therefore, the average angle θ = tan⁻¹ 0.379 = 20.746 ° ≈ 21°.
Answer:
If I am not wrong I think Jeremy is 68" tall
600 miles is the total and a rate of 30 mi per 0.3 in
600 divided by 30 = 20 units
each unit is 0.3 inches
20*0.3 = 6
6 inches
Answer:
Step-by-step explanation:
you have to explain more
When the ball hits the ground, the height is 0.
0 = 100 - 16t²
0 = (10 - 4t)(10 + 4t)
0 = 10 - 4t or 0 = 10 + 4t
4t = 10 or -4t = 10
t =
or t = 
Time cannot be negative (unless you have a time machine) so disregard 
Answer: t =
= 2.5 seconds