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Lapatulllka [165]
3 years ago
8

A satellite is orbiting Earth in an approximately circular path. It completes one revolution each day (86,400 seconds). Its orbi

tal distance is 22,500 kilometers from the Earth's center. What is the satellite's average speed?
a. 5.5 kilometers/second
b. 19.4 kilometers/second
c. 1.64 kilometers/second
d. 384 meters/second
Physics
1 answer:
Vaselesa [24]3 years ago
8 0

Circular path ... circumference = 2π · Radius

Radius = distance from the Earth's center = 22,500 km

Circumference = 2π · 22,500 km = 141,372 km

Speed = (distance to be covered) / (time to cover the distance)

Speed = (141,372 km) / (86,400 seconds)

Speed = (141,372/86,400) (km/sec)

<em>Speed = 1.64 km/sec</em>


<em>Extra Info:</em>

This problem is a nice exercise in Arithmetic, but you shouldn't take any of it to run with in the real world.

A satellite with a period of 1 day is NOT  22,500 km from the center of the Earth.  It's more like 22,500 <u>MILES </u>from the Earth's <u>SURFACE. </u>

The real number is 22,236 miles above sea level, and 26,199 miles (42,164 km) from the center of the Earth.

To do <u>THAT</u> orbit in 86,400 seconds, the satellite has to zip around at <em>3.07 km/sec</em>.

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The diagram shows a position-time graph What is the displacement of the object
algol13

The object is moving, so at different times, it has different displacement.  I'm guessing that you probably want to know the displacement at the end of the time on the graph ... 5 seconds.

Displacement is the distance and the direction FROM (the position at the  beginning) TO (the position at the end).

At the beginning ... time=0 ... the position is 1 meter.

At the end ... time=5 ... the position is zero.

The distance FROM the beginning TO the end is (zero - 1m) .  That's  <em>-1m </em>.


5 0
3 years ago
How much work must be done in the car to slow it from 100km/h to 50km/h
Brilliant_brown [7]

Answer:

-96.465m joule

Explanation:

Let m = mass of the car and v1 = initial velocity and v2 = final velocity

Given.

Initial velocity = 100 km/h

final velocity = 50 km/h

What is work done in the car to slow it from 100km/h to 50km/h?

v1=100km/h=27.78m/s

v2=50km/h=13.89m/s

The work done in the car to slow it from v1 to v2.

w=Δk

w=k2-k1

w= \frac{1}{2}m(v2)^{2}- \frac{1}{2}m(v1)^{2}

w=\frac{1}{2} m(v2-v1)^{2}

w=\frac{1}{2}\times m(13.89 -27.78)^{2}

w=\frac{1}{2}\times m(-13.89)^{2}

w=\frac{1}{2}\times m\times (-192.93)

w=-96.465m joule.

Therefore, the work done is -96.465m joule

7 0
3 years ago
Traditional Indonesian music uses an ensemble called a gamelan that is based on tuned percussion instruments somewhat like gongs
Vlada [557]

Answer:

n = 10 beats

Explanation:

Given:

- Frequency of note f1 = 151 Hz

- Frequency of note f2 = 155 Hz

- The total time they ring t = 2.5 s

Find:

How many beats are heard

Solution:

- The frequency of beat (fb) is the difference between the two frequencies of notes as follows:

                                fb = f2 - f1

                                fb = 155 - 151

                                fb = 4 Hz

- The number of beats per second is also called beat frequency:

                                n = fb*t

                                n = 4*2.5

                                n = 10 beats

           

3 0
4 years ago
Molten hot magma that cools very slowly can cause ____________ in igneous rock?
kifflom [539]

Answer: crystals

Explanation: intrusive igneous rocks are formed by slow cooling magma which contain crystals

7 0
4 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 19 cm apart. The sound
Vanyuwa [196]

Answer:

Explanation:

The former is the case of constructive interference and the later case relates to destructive interference.

For listener, path difference is the separation of loudspeaker as listener is not standing in between the speaker.

If λ be the wave length

For constructive interference

19 = n λ

For destructive interference

29 = (2n+1) λ / 2

= n λ +  λ / 2

= 19 +  λ / 2

10 =   λ / 2

 λ  = 20 cm

= 0. 20 m

7 0
3 years ago
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