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The coefficient of cubical expansion of a substance depends upon

zzz [600]

I think that the coefficient of cubical expansion of a substance depends on THE CHANGE IN VOLUME.

Cubical expansion, also known as, volumetric expansion has the following formula:

Δ V = β V₁ ΔT

V₁ = initial volume of the body
ΔT = change in temperature of the body
β = coefficient of volumetric expansion.

β is defined as the increase in volume per unit original volume per Kelvin rise in temperature.

With the above definition, it is safe to assume that the coefficient of cubical expansion of a substance depends on the change in volume, which also changes in response to the change in temperature.

7 0

3 years ago

How are some types of collisions different from others?

lyudmila [28]

There are two general types of collisions, inelastic and elastic.
Inelastic collisions occur when two objects collide but neither of them bounce away from each other.
Collisions in which the objects do not touch each other are elastic. (Ex: Rutherford Scattering)

3 0

3 years ago

Bending of light as it travels through water droplets will result in what

miv72 [106K]

Refraction is the bending of light

4 0

3 years ago

When two or more different capacitors are connected in series across a potential source, which of the following statement must b

vova2212 [387]

Answer:

C. Each capacitor carries the same amount of charge.

Explanation:

When two or more different capacitors are connected in series across a potential source, each capacitor carries the same amount of charge.

In a series connected capacitor, sane amount of charge flows through the capacitors while different potential difference is passed across them.

The capacitors have the same charge as the charge flowing out directly from the potential source called emf since the emf is the driving force of charge in a circuit.

6 0

3 years ago

An American Red Cross plane needs to drop emergency supplies to victims of a hurricane in a remote part of the world. The plane

Andreas93 [3]

Refer to the diagram shown below.

Assume that air resistance is ignored.

Note:
The distance, h, of a falling object with initial vertical velocity of zero at time t is
h = (1/2)gt²
where
g = 9.8 m/s²

The initial vertical velocity of the supplies is 0 m/s.
It the time taken for the supplies to reach the ground is t, then
(50 m) = (1/2)*(9.8 m/s²)*(t s)²

Hence obtain
t² = 50/4.9 = 10.2041
t = 3.1944 s

The horizontal distance traveled at a speed of 100 m/s is
d = (100 m/s)*(3.1944 s) = 319.44 m

Answer: 319.4 m (nearest tenth)

3 0

4 years ago