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Deffense [45]
3 years ago
12

The diagram shows a position-time graph What is the displacement of the object

Physics
1 answer:
algol133 years ago
5 0

The object is moving, so at different times, it has different displacement.  I'm guessing that you probably want to know the displacement at the end of the time on the graph ... 5 seconds.

Displacement is the distance and the direction FROM (the position at the  beginning) TO (the position at the end).

At the beginning ... time=0 ... the position is 1 meter.

At the end ... time=5 ... the position is zero.

The distance FROM the beginning TO the end is (zero - 1m) .  That's  <em>-1m </em>.


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What is the mass of a person who weighs 653 N at earths surface
miss Akunina [59]

Answer:

66.6 kg

Explanation:

The weight of a person at Earth's surface is given by

W=mg

where

m is the mass of the person

g=9.8 m/s^2 is the acceleration of gravity

The person in the problem has a weight of

W = 653 N

Therefore, we can rearrange the equation to find his mass:

m=\frac{W}{g}=\frac{653}{9.8}=66.6 kg

7 0
4 years ago
Which of the following represents units of geologic time in increasing order?
nordsb [41]

B. is the correct answer.

4 0
4 years ago
Read 2 more answers
Which of the following could you do to increase the strength of an electromagnet?
Ann [662]
Wrap around a metal with wire instead of using wire alone.
8 0
3 years ago
In 1865, Jules Verne proposed sending men to the Moon by firing a space capsule from a 220-m-long cannon with final speed of 10.
Sidana [21]

Answer:

The unrealistically large acceleration experienced by the space travelers during their launch is 2.7 x 10⁵ m/s².

How many times stronger than gravity is this force? 2.79 x 10⁴ g.

Explanation:

given information:

s = 220 m

final speed, vf = 10.97 km/s = 10970 m/s

g = 9.8 m/s²

he unrealistically large acceleration experienced by the space travelers during their launch

vf² = v₀²+2as, v₀ = 0

vf² = 2as

a =vf²/2s

  = (10970)²/(2x220)

  = 2.7 x 10⁵ m/s²

Compare your answer with the free-fall acceleration

a/g = 2.7 x 10⁵/9.8

a/g = 2.79 x 10⁴

a = 2.79 x 10⁴ g

7 0
3 years ago
Express 9.39 x 109 seconds in terms of days.
Natali5045456 [20]
<span> In 1 day there are 24 hours x 60 min/hour x 60 seconds/min = 86 400 seconds

So divide 9.39 x 10^9 by 86 400 to determine the # of days there are

= (9.39 x 10^9) ÷ (8.64 x 10^4)
= (9.39 ÷ 8.64) x (10^9 ÷ 10^4)
= 1.0868055556 x 10^5
= 108 681 (nearest whole day) </span>
4 0
3 years ago
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