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EleoNora [17]
3 years ago
14

Which expression is equivalent to

" -3^{-4} " align="absmiddle" class="latex-formula">
Mathematics
2 answers:
djyliett [7]3 years ago
8 0
 ITS THE SAME AS SAYING -1/3 TO THE FOURTH.  SO  -3X-3=9X-3=-27X-3=81 BUT NOW BECAUSE ITS TO THE ^-4 IT WOULD MAKE IT 1/81
galben [10]3 years ago
5 0
I'm back lol

-3^(-4) = -(1/3)^4 = -1/81
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In a sale all prices are reduced by 10% .What is the sale price of an article marked AED 75.
rusak2 [61]

Answer:

67.5

Step-by-step explanation:

  1. When you calculate the 10% of AED75, it is equal to AED7.5
  2. Then you subtract AED7.5 from AED75 which is AED67.5
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I need help on 12 and 13
Jlenok [28]
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12) 24 x 10^4 
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How would I solve 3+x=9?
kotegsom [21]

Answer:

x=6

Step-by-step explanation:

3+x=9

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A new car sells for $18,000 but it will depreciate over time. After just one year,
WITCHER [35]

Answer:

a.) 18000 x (0.88)^x

x=number of years

b.) value after 10 yrs is represented by

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Step-by-step explanation:

8 0
3 years ago
A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0
3 years ago
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