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3 years ago

What pattern exists in the three places in each period?

Mathematics

1 answer:

alukav5142 [94]3 years ago

3 0

Answer:

the pattern is (hundreds, tens, ones)
963 thousand 104

Step-by-step explanation:

a) Each place in our decimal place-value number system has a name. In the number 356,039, the left-most digit 3 is in the hundred-thousands place, so it is read (by itself) as "three hundred thousand." Together, the digits 356 of that number signify three hundred fifty-six thousand. They are said to be in the "thousands period." Each period of three digits will be grouped like that to specify the number of hundreds, tens, and ones in the period.

b) The given expanded form adds up to give ...

963,104

Based on the above discussion, the name of this number is ...

"nine hundred sixty-three thousand one hundred four"

Using digits to help write this, it would be 963 thousand 104.

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Troyanec [42]

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3 years ago

What of the following exponential functions is represented by the data in the table?

patriot [66]

Answer:

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Step-by-step explanation:

The function is

f(x) = (1/3) ^ (x)

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when x=2 f(x) = 1/9

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2 years ago

1 David buys 4 kg of apples from the supermarket for £1.60.

liberstina [14]

Answer:

£ 2.8

Step-by-step explanation:

4 kg = 1.60

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3 years ago

Please help me answer this <br><br> Explain you’re answer <br><br> Will give braisnlt

choli [55]

Answer:

Concept: Math Analysis

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3 years ago

The length of a rectangle is (t – 8) units, and its width is ('+ 11) units. Which expression can represent the area of the recta

AVprozaik [17]

Corrected Question:

The length of a rectangle is (t – 8) units, and its width is (t + 11) units. Which expression can represent the area of the rectangle?

Answer:

t² + 3t - 88

Step-by-step explanation:

Given:

Rectangle of;

length = (t - 8) units

width = (t + 11) units

The area A of a rectangle is given by;

A = length x width ----------------------------------(i)

Substitute the given length and width into equation (i) as follows;

A = (t - 8) x (t + 11) [expand the brackets]

A = t² -8t + 11t - 88

A = t² + 3t - 88

Therefore, the area is

(t² + 3t - 88) square units

8 0

3 years ago