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Mashutka [201]
3 years ago
15

If an object has a density of 4.2 g/mL, what is its density in hg/L?

Chemistry
2 answers:
Oksi-84 [34.3K]3 years ago
6 0

Your answer would be 42 hg/L

alekssr [168]3 years ago
4 0

I believe "h" stands for hecta-, which means "one hundred."

I will convert from g to hg (divide by 100), then from mL to L (multiply by 1000).

\frac{4.2g}{mL}*\frac{1hg}{100g}*\frac{1000mL}{1L}=42\frac{hg}{L}

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Enter your answer in the provided box.
Lina20 [59]

Answer:

5.06atm

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 1.34 atm

P2 = ?

V1 = 5.48 L

V2 = 1.32 L

T1 = 61 °C = 61 + 273 = 334K

T2 = 31 °C = 31 + 273 = 304K

Using P1V1/T1 = P2V2/T2

1.34 × 5.48/334 = P2 × 1.32/304

7.34/334 = 1.32P2/304

Cross multiply

334 × 1.32P2 = 304 × 7.34

440.88P2 = 2231.36

P2 = 2231.36/440.88

P2 = 5.06

The final pressure is 5.06atm

6 0
2 years ago
What is the average kinetic energy of any substance at 0 K?
Aloiza [94]
The answer is zero!

let me know if you need help with anything else! :)
5 0
3 years ago
Read 2 more answers
A. what is the e value for the oxidation of cytochrome c by the cua redox center in complex iv when the ratio of cyt c (fe3 ) /c
mariarad [96]

0.116 V is the e value for the oxidation of cytochrome c by the cue redox center in complex iv when the ratio of cyst c (fe3 ) /cyst c (fe2 ) is 20 and the ratio of cue (cu2 )/cue (cu ) is 3.

<h3>Explain the process of oxidation of cytochrome c.</h3>

When cytochrome c is oxidized by mitochondrial cytochrome oxidase (COX), it attaches to Apaf-1 to produce the apoptozole, which activates pro-caspase-9 and causes cell death. Cyst can be created from cytosolic cytochrome c. In the IMS, oxidized cytochrome c can scavenge superoxide without converting it into H2O2, a process that happens naturally but is accelerated by SOD. The benefit of scavenging superoxide independently of H2O2 synthesis is reducing the possibility of hydroxyl radical generation via the Fenton reaction.

To learn more about the oxidation of cytochrome c, visit:

brainly.com/question/14473523

#SPJ4

8 0
10 months ago
15. You have a solution of .835mol of NaCl in 2.5L of solution, what is the molarity?
Viktor [21]

Answer: 0.334mol/L

Explanation:

M=\frac{mol}{L}

M=\frac{0.835mol}{2.5L} \\M=0.334mol/L

5 0
2 years ago
Convert the following into balanced equations. ( Use the lowest possible coefficents)?(a) When gallium metal is heated in oxygen
ehidna [41]

Answer:

Explanation:

(a) Balanced reaction of gallium with oxygen is as follows:

4Ga(s)+3O_2(g) \rightarrow 2Ga_2O_3 (s)

(b) C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+H_2O(l)

Multiply the carbon dioxide by 6 to balance carbon as follows:

C_6H_{14}(l)+O_2(g)\rightarrow 6CO_2(g)+H_2O(l)

After that multiply H2O by 7 to balance hydrogen as follows:

C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+7H_2O(l)

Finally balance oxygen by multiplying O2 by 19/2. Therefore, balanced reaction is as follows:

C_6H_{14}(l)+\frac{19}{2} O_2(g)\rightarrow 6CO_2(g)+7H_2O(l)

(c) Na_3PO_4(s)+CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

first balance calcium, by multiply CaCl_2 by 3 as follows:

Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

After that balance phosphorous by multiplying Na_3PO_4 by 2 as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

Finally balance Na by multiplying NaCl by 6. Therefore, balance reaction is as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+6NaCl

3 0
3 years ago
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