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Musya8 [376]
3 years ago
12

Doctors use the radioactive isotope chromium-51 to label red blood cells in the human body. Chromium-51 gives off relatively ___

___ alpha particles that can be stopped by _______ .
Chemistry
2 answers:
Airida [17]3 years ago
7 0
Alpha particles are relatively heave and can be stopped by a sheet of paper.
xz_007 [3.2K]3 years ago
6 0

Answer:

The given blanks can be filled with harmless and a sheet of paper.

Explanation:

Chromium-51 is a chromium’s radioactive isotope. It has an application in medical diagnosis, as it is used to mark RBCs for the determination of red cell volume or mass, sequestration studies, survival time, and for the determination of gastrointestinal bleeding, and is utilized to mark platelets to examine their survival.  

The chromium-51 gives off relatively harmless alpha particles, which can be even prevented by a sheet of paper. The alpha particles do not exhibit a high concentration of energy and are not very ionizing, as they possess a high mass. This makes them comparatively safer to function with.  

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The seven dots around flourine are the valence electrons
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The concentration of pb2+ in a solution saturated with pbbr2(s) is 2.14 ✕ 10-2 m. calculate ksp for pbbr2.
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Concentration = 2.14 âś• 10-2 m 
For [Br-], there are 2 ions so 2 x 2.14 x 10^-2 =4.28 x 10^-2  
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Which of the following would be found in both eukaryotic AND prokaryotic cells?
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Nucleus ,endoplasmic reticulum
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An oily liquid with a cheesy, waxy odor like that of goats or other barnyard animals is caproic acid, a compound containing carb
Zinaida [17]

The empirical formula for the caproic acid, given the combustion analysis data is C₃H₆O

We'll begin bey obtaining the mass of carbon, hydrogen and oxygen in the compound. This is illustrated below:

How to determine the mass of C

  • Mass of CO₂ = 9.78 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 9.78

Mass of C = 2.67 g

How to determine the mass of H

  • Mass of H₂O = 20.99 g
  • Molar mass of H₂O = 18 g/mol
  • Molar of H = 2 × 1 = 2 g/mol
  • Mass of H =?

Mass of H = (2 / 18) × 4

Mass of H = 0.44 g

How to determine the mass of O

  • Mass of compound = 4.30 g
  • Mass of C = 2.67 g
  • Mass of H = 0.44 g
  • Mass of O =?

Mass of O = (mass of compound) – (mass of C + mass of H)

Mass of O = 4.30 – (2.67 + 0.44)

Mass of O = 1.19 g

<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as follow:

  • C = 2.67 g
  • H = 0.44 g
  • O = 1.19 g
  • Empirical formula =?

Divide by their molar mass

C = 2.67 / 12 = 0.2225

H = 0.44 / 1 = 0.44

O = 1.19 / 16 = 0.074

Divide by the smallest

C = 0.2225 / 0.074 = 3

H = 0.44 / 0.0744 = 6

O = 0.074 / 0.074 = 1

Thus, the empirical formula of the compound is C₃H₆O

Learn more about empirical formula:

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Answer: The average person drinks 8 cups per day, equaling to 1/2 gallon per day and 182.5 gallons per year.

Explanation:

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