Answer:
Star's
Explanation:
Stars have their own brightness
This family (ethane, propane, butane, etc) of materials is likely to have following set of properties.
- The alkanes are non- polar solvents.
- The alkanes are immiscible in water but freely miscible in other non-polar solvent .
- The alkanes are consisting of weak dipole dipole bonds can not breaks the strong hydrogen bond.
- The alkanes having only carbon (C) and hydrogen (H) atom which is bonded by a single bonds only.
- The alkanes posses weak force of attraction that is weak van der waals force of attraction.
The ethane, propane, butane, belong to alkanes family.The alkanes are also considers as saturated hudrocarbons. Ethane is found in gaseous stae Ethane is the second alkane followed by propane followed by butane.
learn about butane
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Answer:
The answer is C) The temperature at which the solid-state turns into liquid
Explanation:
The melting point of a substance is the temperature at which it shifts state from solid to liquid. At the melting point, the solid and liquid levels exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change. This occurs when the internal energy of the solid increases, commonly by the application of heat or pressure, which increases the substance's temperature to the melting point.
Answer:
You are not using properly the function exponential in your calculator
Explanation:
When a number is too big or too small we use scientific notation. This is a number between 1 a 10 multiplied by a power of 10.
When you are writing 4.5*10^-9 you are actually writing 0.0000000045 in scientific notation.
When you enter this in the calculator you have to use the function EXP after the first two numbers.
Steps: 1) Enter 4.5
2) Enter EXP
3) Enter minus (-)
4) Enter 9
Answer:
0.752 J/g*K
Explanation:
The heat lost by the alloy (which is negative) must be equal to the heat gained by the water and the coffee cup:
-Qa = Qw + Qc
-ma*ca*ΔTa = mw*cw*ΔTw + C*ΔTc
Where, m is the mass, c is the specific heat capacity, C is the heat capacity of the coffee cup, ΔT is the change in temperature, a represents the alloy, and w the water.
The coffee cup has initial temperature equal to the water, then:
-30.5*ca*(31.1 - 95.0) = 49.3*4.184*(31.1 - 24.3) + 9.2*(31.1 - 24.3)
1948.95ca = 1465.20
ca = 0.752 J/g*K
